Answer:
A. 0.1700
b. 0.00400
c. 0.08000
Step-by-step explanation:
Answer:
1/3, 0.32, 30 percent, 1/5
Step-by-step explanation:
make them all decimals:
1/3 = 0.3333.
30 percent= 0.3
1/5= 0.2
0.32
C = 5p + 200
her folks are willing to spend 295....so c = 295....so sub in 295 for c and solve for p, the number of people that can attend
295 = 5p + 200
295 - 200 = 5p
95 = 5p
95/5 = p
19 = p <=== so 19 people can attend the party
An expression for that would be 10u
Answer:
a) X[bar]₁= 1839.20 cal
b) X[bar]₂= 1779.07 cal
c) S₁= 386.35 cal
Step-by-step explanation:
Hello!
You have two independent samples,
Sample 1: n₁= 15 children that did not eat fast food.
Sample 2: n₂= 15 children that ate fast food.
The study variables are:
X₁: Calorie consumption of a kid that does not eat fast food in one day.
X₂: Calorie consumprion of a kid that eats fast food in one day.
a)
The point estimate of the population mean is the sample mean
X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal
b)
X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal
c)
To calculate the sample standard deiation, you have to calculate the sample variance first:
S₁²=
[∑X₁² - (( ∑X₁)²/n₁)]=
= 149263.4571 cal²
S₁= 386.35 cal
I hope it helps!