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3 years ago

Which character formatting effect makes text appear in a small font size below the midpoint of a line of text

Computers and Technology

1 answer:

pav-90 [236]3 years ago

4 0

Answer:

Superscript or Subscript

Explanation:

The superscript or the subscript is a type of character which is set a little lower or more than the normal line of type. And it is generally small as compared to the other texts. The subscript does appear at or less than the baseline, and the superscript is above. And for the superscript, you need to press the Ctrl + Shift + + ( press and at the same time also hold the Ctrl and the Shift, and finally press the +). And for the subscript, you need to press the Ctrl + Shift ++(Press and at the same time also hold the Ctrl. and finally press the =). And pressing the corresponding shortcut once again, you will be back to the normal text.

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If you wanted to detect x-rays coming from the sun,where would you place the detector? Why?

Temka [501]

You would place it in orbit around Earth, as most X-rays are absorbed by the atmosphere, so you would want the detector outside of the atmosphere to accurately detect the X-rays.

5 0

3 years ago

Which network protocol is used to route IP addresses? A. TCP B. UDP C. IP D. ICMP

ladessa [460]

Answer:

C. IPIP

Explanation:

This protocol is known as an IP that stands for Internet Protocol. This protocol handles the simple task of making sure that the information is routed correctly to and from the corresponding computer machines through the internet. The sending and receiving machines are identified through their Internet Protocol Addresses which lets the protocol know exactly where the information is going and being sent from.

8 0

3 years ago

To print the last element in the array named ar, you can write :A. System.out.println(ar.length);

timofeeve [1]

Answer:

Option (d) is the correct answer.

Explanation:

An Array is used to store multiple variables in the memory in the continuous memory allocation on which starting index value is starting from 0 and the last index value location is size-1.

In java programming language the array.length is used to tells the size of the array so when the user wants to get the value of the last element, he needs to print the value of (array.length-1) location so the correct statement for the java programming language is to print the last element in the array named ar is--

System.out.println(ar[ar.length-1]);

No option provides the above statement, so option d (None of these) is correct while the reason behind the other option is not correct is as follows--

Option a will prints the size of the array.
Option b also gives the error because length is an undeclared variable.
Option c will give the error of array bound of an exception because it begs the value of the size+1 element of the array.

3 0

3 years ago

2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of

allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0

2 years ago

In the ____ letter style, all components of the letter begin flush with the left margin.

Sedaia [141]

In the block letter style, all components of the letter begin flush with the left margin.

4 0

2 years ago