Answer:
90 pounds, 210 pounds
Step-by-step explanation:
<u>Given</u>:
A storekeeper wants to mix two types of flour to get 300 pounds, so he can sell it by 2.50$ per pound.
He uses flour worth $2.40 a pound with another flour worth $3.00 a pound.
<u>Question</u>:
How many pounds of each does he use?
Solution:
Let pounds of one type of flour mixed = ![x](https://tex.z-dn.net/?f=x)
Then pounds of another type of flour mixed = ![300-x](https://tex.z-dn.net/?f=300-x)
Cost of 1 pound of one type of flour = $2.40
Cost of
pounds of one type of flour = ![2.4x](https://tex.z-dn.net/?f=2.4x)
<u>Similarly</u>,
Cost of 1 pound of another type of flour = $3
Cost of
pounds of another type of flour = ![3(300-x)=900-3x](https://tex.z-dn.net/?f=3%28300-x%29%3D900-3x)
Cost of mixed flour per pound = $2.5
Total cost of mixed flour per pound = $2.5
300 = $750
Cost of
pounds of one type + Cost of
pounds of another type = $750
![2.4x+900-3x=750\\\\ -0.6x+900=750\\ \\ Subtracting\ both\ sides\ by\ 900\\ \\ -0.6x+900-900=750-900\\ \\ -0.6x=-150\\ \\ Minus\ canceled\ by\by\ minus\\ \\ 0.6x=150\\ \\ Dividing\ both\ sides\ by\ 0.6\\ \\ x=90](https://tex.z-dn.net/?f=2.4x%2B900-3x%3D750%5C%5C%5C%5C%20-0.6x%2B900%3D750%5C%5C%20%5C%5C%20Subtracting%5C%20both%5C%20sides%5C%20by%5C%20900%5C%5C%20%5C%5C%20-0.6x%2B900-900%3D750-900%5C%5C%20%5C%5C%20-0.6x%3D-150%5C%5C%20%5C%5C%20Minus%5C%20canceled%5C%20by%5Cby%5C%20minus%5C%5C%20%5C%5C%200.6x%3D150%5C%5C%20%5C%5C%20Dividing%5C%20both%5C%20sides%5C%20by%5C%200.6%5C%5C%20%5C%5C%20x%3D90)
Pounds of one type of flour mixed =
= 90 pounds
Pounds of another type of flour mixed =
= 300 - 90 = 210 pounds
Thus, 90 pounds of one and 210 pound of another type of flour mixed.