Prime factorization of 2·5·2=2^2·5
Solve using the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)
REMEMBER: IF NOT APPLICABLE TO THE EQUATION YOU MAY SKIP THAT STEP IN PEMDAS .
3(8 - 2) + 4 = 22
Parentheses...
(15 - 6)² ÷ 3 - 3³
15 - 6 = 9
(9)² ÷ 3 - 3³
Exponent....
9² ÷ 3 - 3³
In this case you have two exponents. Always apply the steps from left to right
9² ÷ 3 - 3³
9² = 81
81 ÷ 3 - 3³
3³ = 27
81 ÷ 3 - 27
Division...
81 ÷ 3 - 27
81 ÷ 3 = 27
27 - 27
Subtraction...
27 - 27 = 0
0
<u>Your mistake: </u>
You subtracted 3 - 27 before dividing 81 by 3. Remember that according to the rules of PEMDAS division must come before subtraction
Hope this helped!
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The function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x
<h3>Reflection of functions and coordinates</h3>
Images that are reflected are mirror images of each other. When a point is reflected across the line y = x, the x-coordinates and y-coordinates change their position. In a similar manner, when a point is reflected across the line y = -x, the coordinates <u>changes position but are negated.</u>
Given the exponential function below
f(x) = 5(0.8)^x
If the function f(x) is reflected over the x-axis, the resulting function will be
-f(x)
This means that we are going to negate the function f(x) as shown;
f(x) = -5(0.8)^x
Hence the function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x
Learn more on reflection here: brainly.com/question/1908648
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The lengths of HJ and JK are 50 and 72 respectively.
Given: J is between H and K. the length of HJ=2x+4, JK=3x+3, and HK=22.
The line HJ and JK are collinear then the total length is given as: HJ+JK=HK
substitute values
⇒ (2x+4)+(3x+3)=22
⇒ 5x+7=22
⇒ 5x=22-7
⇒ 5x=15
⇒ x=3
Thus, the length of HJ is (2x+4)=(2*3+4)=10
And the length of JK is (3x+3)=(3*3+3)=12
Learn more about collinear lines here: brainly.com/question/27943430
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Answer:
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