Answer: 32
Step-by-step explanation:
Let x + y = 5
x = 5 - y....................(1)
10x + y -9 = 10y + x..... . (2)
Substituting (1) in (2)
10(5-y) + y - 9 = 10y + (5-y)
50-10y + y - 9 = 10y + 5 - y
41 - 9y = 9y + 5
-9y - 9y = 5-41
-18y = - 36
y = 36/2 = 2
So, x = 5-2 = 3
We may answer the question above by substituting the values of the coordinates of the points in the choices to the x and y of the inequality.
A. (-2, 4) 4 - 4(-2) ≤ -6 12 ≤ -6 FALSE
B. (1, -2) -2 - 4(1<span>) ≤ -6 -6 ≤ -6 TRUE
C (1, 3) 3</span> - 4(1<span>) ≤ -6 -1 ≤ -6 FALSE
D. (2, 3) 3</span> - 4(2<span>) ≤ -6 -5 ≤ -6 FALSE
The answer would be letter B. </span>
Answer: The correct option is
(E) 70.
Step-by-step explanation: We are given to find the number of triangles and quadrilaterals altogether that can be formed using the vertices of a 7-sided regular polygon.
To form a triangle, we need any 3 vertices of the 7-sided regular polygon. So, the number of triangles that can be formed is

Also, to form a quadrilateral, we need any 4 vertices of the 7-sided regular polygon. So, the number of quadrilateral that can be formed is

Therefore, the total number of triangles and quadrilaterals is

Thus, option (E) is CORRECT.