<h3>
Answer: x = 14</h3>
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Work Shown:
Refer to the diagram below. I've added a line segment and two variables y and z. This forms two isosceles triangles.
The central angle 56 degrees subtends the same arc as the inscribed angle y. By the inscribed angle theorem, this means y = 56/2 = 28. The inscribed angle is always half of the central angle (when both angles subtend the same arc).
Focus on the smaller isosceles triangle that has angles 56, z and z. Those three angles add to 180
z+z+56 = 180
2z+56 = 180
2z = 180-56
2z = 124
z = 124/2
z = 62
Now focus on the larger isosceles triangle (angles y = 28, x+z and x+z)
We'll use the same trick as before.
(x+z)+(x+z)+(y) = 180
(x+62)+(x+62)+(28) = 180 ... plug in z = 62 and y = 28
2x+152 = 180
2x = 180-152
2x = 28
x = 28/2
x = 14
Answer:
2x^2
Step-by-step explanation:
2x*1x= 2x^2
9514 1404 393
Answer:
4.8 years
Step-by-step explanation:
Solving the compound interest formula for the number of years gives ...
t = log(A/P)/(n·log(1 +r/n))
where principal P invested at rate r compounded n times per year produces value A after t years.
t = log(24805/22000)/(365·log(1 +0.025/365)) ≈ 4.800
The loan was for 4.8 years.
Answer:
a_n = 2^(n - 1) 3^(3 - n)
Step-by-step explanation:
9,6,4,8/3,…
a1 = 3^2
a2 = 3 * 2
a3 = 2^2
As we can see, the 3 ^x is decreasing and the 2^ y is increasing
We need to play with the exponent in terms of n
Lets look at the exponent for the base of 2
a1 = 3^2 2^0
a2 = 3^1 2^1
a3 = 3^ 0 2^2
an = 3^ 2^(n-1)
I picked n-1 because that is where it starts 0
n = 1 (1-1) =0
n=2 (2-1) =1
n=3 (3-1) =2
Now we need to figure out the exponent for the 3 base
I will pick (3-n)
n =1 (3-1) =2
n =2 (3-2) =1
n=3 (3-3) =0
You solve for y and get
y=3/4x-5
Slope is 3/4
Y intercept is -5
