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Answer:
0.1463
Step-by-step explanation:
Number of observations = 10
Sample mean = 10.5
Sum of standard deviation = 264.5
X = 14
We are to calculate The leverage statistic for study hour 14 using the data above
= 1/10 + (14-10.5)²/264.5
= 1/10 + 3.5²/264.5
= 0.1 +12.25/264.5
= 0.1+0.04631
= 0.1463 is the leverage statistic for the study
OFFER A is cheaper.
Step-by-step explanation:
Given,
OFFER A
Pack of 5
£2.75
Pay for 3 packs get 1 free
And
OFFER A
Pack of 5
£2.75
Pay for 3 packs get 1 free
To find which offer is cheaper.
<u>For OFFER A</u>
For 4 Packets he needs to pay £2.75
He needs to buy 40 batteries.
He needs to buy 40÷(4×5) = 2 packets.
Total cost = £2.75 ×2 = £5.5
<u>For OFFER B</u>
For 4 Packets he needs to pay £2.52
He needs to buy 40 batteries.
He needs to buy 10 packets.
After discount he has to pay = £2.52
-(£2.52
×) = £1.68
Total cost = £1.68×10 = £16.8
Hence,
OFFER A is cheaper.