3 years ago

How to do number 17.

1 answer:

4 0

$(x^6-4x^5-7x^3)\div(2x^3)=\dfrac{x^6-4x^5-7x^3}{2x^3}\\\\=\dfrac{x^6}{2x^3}-\dfrac{4x^5}{2x^3}-\dfrac{7x^3}{2x^3}=0.5x^{6-3}-2x^{5-3}-3.5\\\\=0.5x^3-2x^2-3.5\\\\Used:\\\\\dfrac{a^n}{a^m}=a^{n-m}$

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