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zavuch27 [327]
3 years ago
7

How to do number 17.

Mathematics
1 answer:
natima [27]3 years ago
4 0

(x^6-4x^5-7x^3)\div(2x^3)=\dfrac{x^6-4x^5-7x^3}{2x^3}\\\\=\dfrac{x^6}{2x^3}-\dfrac{4x^5}{2x^3}-\dfrac{7x^3}{2x^3}=0.5x^{6-3}-2x^{5-3}-3.5\\\\=0.5x^3-2x^2-3.5\\\\Used:\\\\\dfrac{a^n}{a^m}=a^{n-m}

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ivann1987 [24]
Let x be the unknown angle.
We know that x+50=120 because the value of an exterior angle of a triangle is equal to the sum of the other 2 interior angles.

x+50 = 120
Subtract both sides by 50
x = 70

The value of the unknown angle is 70 degrees.

Have an awesome day! :)
5 0
3 years ago
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What is the formula of CP​
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Answer:

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Step-by-step explanation:

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3 years ago
What is the factored form of the expression?<br><br> d^2 = 36d + 324
Veseljchak [2.6K]

Answer:

(x-43.45)(x+7.45)=0

Step-by-step explanation:

We have the quadratic equation d^{2}=36d+324  i.e. d^{2}-36d-324=0

As, the roots of the quadratic equation ax^{2}+bx+c=0 are given by x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}.

So, from the given equation, we have,

a = 1, b = -36 , c = -324.

Substituting the values in x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}, we get,

x=\frac{36\pm \sqrt{(-36)^{2}-4\times 1\times (-324)}}{2\times 1}

i.e. x=\frac{36\pm \sqrt{1296+1296}}{2}

i.e. x=\frac{36\pm \sqrt{2592}}{2}

i.e. x=\frac{36\pm 50.9}{2}

i.e. x=\frac{36+50.9}{2}  and x=\frac{36-50.9}{2}

i.e. x=\frac{86.9}{2}  and x=\frac{-14.9}{2}

i.e. x = 43.45 and x = -7.45

Thus, the roots of the equation are 43.45 and -7.45.

Hence, the factored form of the given expression will be (x-43.45)(x+7.45)=0

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3 years ago
Help me with my little brothers test i have a pdf document of the test and i need a answer key!!
mina [271]

Answer:

c

Step-by-step explanation:

it starts at (0,0) and follows the points best

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