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2 years ago

Given f(x)=3x^2+5 and g(x)=x−2 . What is (fg)(x) ? 3x^2−x+7 3x^3−6x2+5x−10 −3x^2+x−7 3x^3−10

Mathematics

2 answers:

mote1985 [20]2 years ago

8 0

Answer:

(fg)(x) = 3x³-6x²+5x-10

Step-by-step explanation:

We have given two functions.

f(x)=3x²+5 and g(x)=x−2

We have to find (fg)(x).

The formula to find fg is :

(fg)(x) = f(x) × g(x)

Putting values in above formula, we have

(fg)(x) = (3x²+5)(x-2)

(fg)(x) = 3x²(x-2)+5(x-2)

(fg)(x) = 3x³-6x²+5x-10 which is the answer.

wolverine [178]2 years ago

6 0

For this case we have that by definition:

$(fg) (x) = f (x) * g (x)$

So:

$(fg) (x) = (3x ^ 2 + 5) (x-2)$

We apply distributive property that states that:

$(a + b) (c + d) = ac + ad + bc + bd$

In addition, we take into account that:

$+ * - = -$

$(fg) (x) = 3x ^ 3-6x ^ 2 + 5x-10$

Answer:

$3x ^ 3-6x ^ 2 + 5x-10$

Option B

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