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3 years ago

34 + 3 ⋅ 5 = ____. (Input whole numbers only.) Numerical Answers Expected!

Mathematics

1 answer:

vladimir2022 [97]3 years ago

7 0

[ Answer ]

$\boxed{49}$

[ Explanation ]

34 + 3 · 5 = _____

Parenthesis

Exponents

Multiply

Divide

Add

Subtract

Multiply

3 * 5 = 15

Add

34 + 15

Final Answer

$\boxed{[ \ Eclipsed \ ]}$

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0= 8-2x divided by 5

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Answer:

Step 1: Simplify both sides of the equation.

0= 8− $\frac{2x}{5}$

0 = 8 + $\frac{-2}{5}x$

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Step 4: Multiply both sides by 5/(-2).

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3 years ago

1.How many combinations are possible from the letters HOLIDAY if the letters are taken?

Lesechka [4]

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

<h3>What is the combination formula?</h3>

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Exercise 1, item a:

One letter from a set of 7, hence:

$C_{7,1} = \frac{7!}{1!6!} = 7$

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

$C_{7,2} = \frac{7!}{2!5!} = 21$

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

$C_{7,7} = \frac{7!}{0!7!} = 1$

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

$T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245$

There are 245 ways to group them.

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