Standard form: 7z^4-6z^2-6z
This IS a polynomial, it's degree is 4 and has 3 terms
Answer:
4y=x+33
y=x/4+33/4 (slope-intercept form)
Step-by-step explanation:
y-3 = -4(x+2)
y-3 -4x-8
y= -4x-8+3
y= -4x-5
m1 = -4
For perpendicularity
m2= -1/-4 = 1/4
The equation is
y-y1 = m2(x-x1)
y-7 = 1/4(x-(-5))
y-7 = x/4+5/4
Multiply through by 4
4y-28=x+5
4y=x+5+28
4y=x+33
Divide through by 4
y=x/4+33/4 (slope-intercept form)
Answer:
71
Step-by-step explanation:
<u>refer</u><u> </u><u>the</u><u> attachment</u>
to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that <u>tangents </u><u>which</u><u> </u><u>meet </u><u>at</u><u> the</u><u> </u><u>same</u><u> </u><u>point</u><u> </u><u>are </u><u>equal</u><u> </u><u> </u>that is being said
since
and it's given that FA and BA are 17 and 29 FB should be
therefore,
once again by two tangent theorem we acquire:
As BC=BH+CH,BC is
- 12+2.5

likewise,AD=AI+DI so,
- 21=17+DI [AD=21(given) and AI=17 (by the theorem)]
thus,
- DI=21-17=

By the theorem we obtain:
Similarly,DC=DG+CH therefore,
- DC=4+2.5=

Now <u>finding</u><u> </u><u>the</u><u> </u><u>Perimeter</u><u> </u><u>of </u><u>ABCD</u>
substitute what we have and got
simplify addition:
hence,
the Perimeter of ABCD is <u>7</u><u>1</u>