Answer:
10-5+3×3
Step-by-step explanation:
that what you get when you first work out the division sign
Step-by-step explanation:
Given mCDF = (3x + 14), mFDE = (5x - 2), and mCDE = (10x – 18)", then the expression mCDE = mCDF+mFDE is true.
To get x, we will substitute the given angles into the formula as shown;
(10x – 18) = (3x + 14)+ (5x - 2)
10x-18 = 3x+5x+14-2
10x-18 = 8x+12
10x-8x = 12+18
2x = 30
x = 30/2
x = 15
Find the measure of each angle
For mCDF:
mCDF = 3x + 14
mCDF = 3(15)+ 14
mCDF = 45+14
mCDF = 59°
For mFDE:
mFDE = (5x - 2)
mFDE = 5(15) - 2
mFDE = 75-2
mFDE = 73°
For mCDE:
mCDE = (10x – 18)
mCDE = 10(15) - 18
mCDE = 150-18
mCDE = 132°
Hello Friend,here is the solution for your question
<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)
Now here in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2) is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>
And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0 [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>
<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
=√[1/8-3(0)] [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
=√1/8
=1/(2√2)
<span>this is the maximum value now to find the minimum value </span>
<span>since this is function of root so the value of y will always be ≥0 </span>
<span>hence the minimum value of the function y is 0 </span>
<span>Therefore, the range of function </span>y is [0,1/(2√2)]
__Well,I have explained explained each and every step,do tell me if you don't understand any step._
Answer: they are both the same fraction
