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3 years ago

What is 3/4 of the product of 2/4 and 6/8?

Mathematics

1 answer:

joja [24]3 years ago

7 0

Answer:

6/8 the product of 2/4and6/8

Step-by-step explanation:

2/4and6/8=4/8,12/16

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Someone came into my shop and stole $100.00 from the register without my knowledge. The person came back in with the same $100.0

Talja [164]

You 'lost' 100 dollars in sales and liquid cash. However, you are only missing 30 dollars.

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3 years ago

Read 2 more answers

The length of a rectangle is 2 units shorter than one-fifth of the width, x.

sergey [27]

Answer:

C. $P=\frac{12x}{5} + 4$

Step-by-step explanation:

Width = x

Length = one fifth of width minus 2

Length = $\frac{1}{5}x-2$

Perimeter is given by the formula

$P=2(l+b)$

$P=2(\frac{1}{5}x-2+x)$

$P=2(\frac{x}{5}-2+x)$

$P=2\times \frac{x-2 \times 5+5 \times x}{5}$

$P=2\times \frac{x-10+5x}{5}$

$P=2\times \frac{6x}{5} - 2\times \frac{-10}{5}$

$P=2\times \frac{6x}{5} + 2\times \frac{10}{5}$

$P=\frac{12x}{5} + 4$

5 0

3 years ago

Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0

miss Akunina [59]

<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^2+y^2-2x+4y-11=0$

So, solving we have:

$x^2+y^2-2x+4y=11$

$(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16$

$(x^2-1)+(y^2-(-2))=16$

Now, we have that:

$h=1\\k=-2\\r=\sqrt{16}=4$

So,

Center: (1,-2)

Radius: 4 units.

Have a nice day!

Note: I have attached a picture for better understanding.

5 0

4 years ago

Draw a Hasse diagram of the partial order << of the set {2,3,4,6,8,9,10,12} where a << b iff b is divisible by a.

Ray Of Light [21]

Step-by-step explanation:

Consider the provided set {2,3,4,6,8,9,10,12}

Let the set is A.

$A={(2 \prec 4), (2 \prec 6), (2 \prec 8), (2 \prec 10), (2 \prec 12), (3 \prec 6), (3 \prec 9), (4 \prec 8), (4 \prec 12), (6 \prec 12)}$

Hence the required Hasse diagram is shown in figure 1:

In the Hasse diagram 2 and 3 are on the same level as they are not related.

The next numbers are 4, 6, 9, and 10. 4, 6 and 10 are divisible by both 2. 6 and 9 are divisible by 3. Then 8 and 12 are divisible by 4 also 12 is divisible by 6.

Hence, the required diagram of the partial order of the set {2,3,4,6,8,9,10,12} is shown in figure 1.

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3 years ago

Use the laplace transform to solve the given initial-value problem. y' − 2y = (t − 4), y(0) = 0

yulyashka [42]

Using the Laplace transform, the value o y' − 2y = (t − 4), y(0) = 0 is⇒y(t) = 0 e^-t + u(t -1)e^1-t

Laplace rework is an critical rework approach that is in particular useful in fixing linear normal equations. It unearths very huge applications in regions of physics, electrical engineering, control optics, arithmetic and sign processing.

y' − 2y = (t − 4),

y(0) = 0

Taking the Laplace transformation of the differential equation

⇒sY(s) - y (0) + Y(s) = e-s

⇒(s + 1)Y(s) = (0+ e^-s)/s + 1

⇒y(t) = L^-1{0/s+1} + {e ^-s/s + 1}

⇒y(t) = 0 e^-t + u(t -1)e^1-t

The Laplace remodel method, the feature within the time area is transformed to a Laplace characteristic within the frequency domain. This Laplace feature will be inside the shape of an algebraic equation and it can be solved easily.

Learn more Laplace transformation here:-brainly.com/question/14487437

#SPJ4

4 0

2 years ago

What is 3/4 of the product of 2/4 and 6/8?​

What is 3/4 of the product of 2/4 and 6/8?