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Galina-37 [17]
3 years ago
5

Prove the quotient rule. hint: you can do this directly, but it may be easier to find the derivative of 1/x and then use the cha

in rule and the product rule
Mathematics
1 answer:
Bess [88]3 years ago
5 0
The quotient rule is
d(u/v) = (u dv - v du) / u2

d(u/v) can written as
d( u (1/v) )

Using the product rule and chain rule
d( u (1/v)) = u d(1/v) + (1/v) du
= u (-1/v2) dv + (!/v) du
= (u dv - v du) / u2
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80 % of _ games is 32 games
andrew-mc [135]
80% × x = 32
.80x = 32
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3 years ago
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A sweater is marked 30% off during an end or season sale. If the sweater was originally $56.00, what is the sale price of the sw
Ludmilka [50]

Answer:

Sweater costs 56.00

To calculate the discounted price of the sweater

56 * (30/100) = 16.8

We used (30/100) to find out the 30 percent of the sweater which will be on discount/reduced.

56-16.8=39.2 is the discounted price

Then we subtract the amount of discount from the original price of sweater to find out the discounted price.

Step-by-step explanation:

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2 years ago
Does this graph represents a function? Why or why not?
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Answer:

B. Yes, because it passes the vertical line test.

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3 0
3 years ago
Question:
DanielleElmas [232]

Given A room is half as long again as it is broad

Let the breadth of the room x m

length of the room x + x/2 = 3x/2m

Area of the room , x × 3x/2 =<em> 3x²/2m</em>

Given , cost of carpeting the room at Rs. 3.25m⁻²

So , total cost , 3x²/2 × 3.25

But , Total cost of carpeting is given as 175.50 so ,

  • (3x²/2 )× 3.25 = 175.50
  • x² = 175.50 × 2 / 3.25 × 3
  • x² = 36
  • x = 6

  • Breadth x = 6 m
  • length 3x/2 = 9m

let the height of the room H m

Area of the four wall = 2(L+ b)× h 2(6+9)× H

= 30H m²

Area of the of the one door and two window is 8m²

8m² Area to be prepared = Area of four wall - area of two window and 1 door = (30H - 8) m²

Given cost of preparing wall is Rs. 1.40m²

total cost of preparing wall is (30H - 8) × 1.40

Total cost of preparing wall is given as 240.80

comparing , (30H - 8 ) × 1.40 = 240.80

  • (30H - 8 ) = 240.80 /1.40 = 172
  • 30H -. 8 = 172
  • 30H = 180
  • H = 180/30 = 6

Hence, Dimensions of the room are lengths 9m , breadth 6m and height 6m

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3 years ago
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83 tents and they only need 82.75 tents because 331 divided by 4 is 82.75
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