As it is, in accordance with the priorities of the operators (or the PEMDAS rule) the equation without parentheses mean
<span>(2/3)x+1=(1/6)x-7
I do not suppose you mean the above, since the solution is relatively trivial.
I suppose you actually mean
</span><span>2/(3x+1)=1/(6x-7)
in which case you would cross-multiply:
2(6x-7)=(3x-1)
and expand/distribute
12x-14=3x-1
isolate x and solve
12x-3x=-1+14
9x=13
x=13/9
If you mean the first form of equation without parentheses, my apologies.</span>
Answer:
for the second question u have asked
Step-by-step explanation:
-x^2 + 4 = 2x + 1
-x^2 - 2x + 4 - 1 = 0
-x^2 - 2x + 3 = 0
(x + 3)(-x + 1)= 0
x + 3 = 0 -x + 1 = 0
x = -3 -x = -1
x = 1
so x = -3 and x = 1
Answer:
Step-by-step explanation:
So we have the equation:
First, separate the second term:
Let u equal 5ˣ. So:
Combine like terms:
Divide both sides by 6:
Substitute back u:
Take the base 5 logarithm of both sides:
The left cancels:
Evaluate the right:
So, our answer is 2.
And we're done!
