For the equation y=7x+3 the value of X changes from 1 to 2

2 answers:

8 0

When x=1, 7x+3 = 10. When x=2, 7x+3 = 17. When the value of 'x' changes from '1' to '2', the value of 7x+3 changes from '10' to '17' . . . a distance of '7' . That's what the ' 7x ' in the equation means, and that's what we mean when we say that the 'slope' of the equation is '7'. 'y' changes '7' for every '1' that 'x' changes. Hope this helps :))

WITCHER [35]3 years ago

5 0

When x=1, 7x+3 = 10.

When x=2, 7x+3 = 17.

When the value of 'x' changes from '1' to '2', the value of 7x+3 changes
from '10' to '17' . . . a distance of '7' .

That's what the ' 7x ' in the equation means, and that's what we mean
when we say that the 'slope' of the equation is '7'. 'y' changes '7' for
every '1' that 'x' changes.

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Among a sample of 55 male soldiers the average shower time was found to be 2.95 minutes and the population standard deviation is

Oksanka [162]

Answer: -3.0593

Step-by-step explanation:

The test statistic for the difference between two population mean (when population standard deviations $\sigma_1\ \&\ \sigma_2$ are known ) is given by :-

$z=\dfrac{\overline{x}_1-\overline{x}_2}{\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}}$

where ,

$n_1\ \&\ n_2$ = Sample sizes taken from two populations 1 and 2.

$\overline{x}_1-\overline{x}_2$ = Difference between two Sample mean.

$\sigma_1\ \&\ \sigma_2$ = Standard deviations of populations 1 and 2.

As per given , we have

$n_1=55\ \&\ n_2=58$

$\overline{x}_1=2.95\ \&\ \overline{x}_2=3.3$

$\sigma_1=0.65\ \&\ \sigma_2=0.56$

We assume that the data follows a normal distribution.

Then, the test statistic will be :-

$z=\dfrac{2.95-3.3}{\sqrt{\dfrac{(0.65)^2}{55}+\dfrac{(0.56)^2}{58}}}\\\\=\dfrac{-0.35}{\sqrt{0.0130887}}\\\\=\dfrac{-0.35}{0.1144059}=3.05928278174\approx-3.0593$