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3 years ago

604,016 in expanded Form

Mathematics

1 answer:

Charra [1.4K]3 years ago

6 0

600,000 + 4,000 + 10 + 6

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The basket of golf balls at a miniature golf course contains 18 golf balls, of which 9 are red. What is the probability that a r

alexira [117]

It will be 2 because 19/9 is 2

5 0

3 years ago

Read 2 more answers

John's patio is 5 feet long<br> and has an area of 1.30<br> square feet<br> How wide is the patio?

Sophie [7]

Step-by-step explanation:

so, I assume the patio is a true rectangle.

the area of a rectangle is

length × width

in our case that means

1.3 = 5 × width

width = 1.3 / 5 = 0.26 ft

so, this is just a very narrow strip of 0.26ft × 5 ft.

I would not call that a patio ...

or was it a typo, and the area is actually 30 ft² ?

then we would have

30 = 5 × width

width = 30 / 5 = 6 ft

7 0

3 years ago

A 98% confidence interval for the mean of a population is to be constructed and must be accurate to within 0.3 unit. A prelimina

BaLLatris [955]

Answer:

$n = (\frac{2.326*1.7}{0.3})^2= 173.73$

And the value for n rounded up would be n = 174

Step-by-step explanation:

We have the following info given:

$s= 1.7$ previous estimation for the deviation

$ME=0.03$ the margin of error desired

$Conf =0.98$ represent the confidence

The Margin of error is given by:

$ME = z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

If we solve for the value of n we got:

$n= (\frac{z*\sigma}{ME})^2$

For this problem we know that the confidence is 98% so then the significance level would be $\alpha=0.02$ and the critical value would be:

$z_{\alpha/2}= 2.326$

And replacing we got:

$n = (\frac{2.326*1.7}{0.3})^2= 173.73$

And the value for n rounded up would be n = 174

3 0

3 years ago

5. A gold bar weighs 12.6 kg. How many grams does the gold bar weigh?

charle [14.2K]

Answer:

12600 g

Step-by-step explanation:

a kilogram is a thousand grams

(don't forget to include units)

7 0

3 years ago

Read 2 more answers

Determine if the lim f(x) exists using the graph below.. If it does, find its value. If it does not,x 1explain why

Leno4ka [110]

The limit of a function f at a point a exists if:

$\lim_{x\to a^-}f(x)=\lim_{x\to a^+}f(x)$ $\begin{gathered} \text{ From the given image, the value of the left limit of f at x=1 } \\ \lim_{x\to a^-}f(x)\lt1 \end{gathered}$

Also,

$\begin{gathered} \text{ From the given image, the value of the right limit of f at x=1 } \\ \lim_{x\to a^+}f(x)\gt1 \end{gathered}$

Therefore,

$\lim_{x\to1^-}f(x)\lim_{x\to1^+}f(x)$

Hence, the limit does not exist

8 0

1 year ago