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galina1969 [7]
3 years ago
10

If M is the set of all square of integers that are less than 100 and N is the set of all positive even numbers that are under 30

Find M∩N and M∪N
Mathematics
1 answer:
ozzi3 years ago
8 0

M

=

100

=

N

=

30

=

M

∩

N

=

M

∪

N

=

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Can someone please help me with this?!
Alinara [238K]

Answer: y=\frac{1}{4}x-3


Step-by-step explanation:

- The equation of the line in the slope intercept form is: y=mx+b

Where m is the slope and b is the y-intercept of the line

- Let's choose two points of the line: (8,-1) and (-4,-4).

- You must calculate the slope of the line as following:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-4-(-1)}{-4-8}=\frac{1}{4}

- As you can see in the graph attached, the line intersects the y-axis at -3, then b=-3.

- Substituting values into the equation of the line, you obtain:

y=\frac{1}{4}x-3


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3 years ago
Please help me!! Question is on the image
Flura [38]

Answer:

42

Step-by-step explanation:

8+8+12+4+4+3+3

Something like this for the problem.

4 0
4 years ago
How many variable terms are in the expression 3x^y + 5x^ - 4y + z + 9?
Bess [88]
The number of variables in the problem is 3
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3 years ago
Interpret the following table about school dropout at the basic level (5 marks)
barxatty [35]

Answer:

Step-by-step explanation:

Given the following :

- - - Jhs

Basic level - - - - Boys - - - - Girls - - - - Total

Primary - - - - - - - 49 - - - - - - 51 - - - - - - 100%

Jhs - - - - - - - - - - 56 - - - - - - 44. - - - - - - 100%

With the information above,

Primary Dropout percentage:

BOYS : [49 / (49 +51)] × 100.= 49%

GIRLS : [51 / (49 +51)] × 100.= 51%

Jhs: Dropout percentage

BOYS : [56 / ( 56 + 44) × 100 = 56%

GIRLS : [44 / (44 +56)] × 100.= 44%

8 0
3 years ago
PLEASE ANSWER FOR BRAINLIEST!!
e-lub [12.9K]

Answer:

mFG = 67r ( Where r is the radius of the circle)

∠ECF = 67°

Step-by-step explanation:

i) m FG

Join CG

∠GCF=67°

(As FG=ED and equal chords subtend equal angle at center)

Now The length of the minor arc is given by the formula

m arc FG =

\frac {C}{2 \pi} \times 2 \pi r

∠C=67

m arc FG = \frac {67}{2 \pi} \times 2 \pi r

m arc FG = 67r

Where r is the radius of the circle.

2. ∠ECF = 67°

It is because of the rule which says that equal chords subtend equal angle at center

DE = EF

Hence ∠DCE = ∠ECF

7 0
3 years ago
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