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3 years ago

9

Please Help !!!!!!!!

2 answers:

spin [16.1K]3 years ago

8 0

-3x+ 5

Use the key above to count the rectangles and squares.

Ymorist [56]3 years ago

6 0

-3x + 5...I hope this helps

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X is a number such that 7x=7y

Delicious77 [7]

X= y

u have to divide 7 from both sides

8 0

4 years ago

HELP ASAP ASAP ASAP ASAP ASAP ASAP

pishuonlain [190]

Answer:

x = 35 feet.

Step-by-step explanation:

Given that,

The height of the person is 5 feet.

The height of the flag and the eye is (x-5) feet.

We can calculate using trigonometry.

$\tan\theta=\dfrac{(x-5)}{30}\\\\\tan(45)=\dfrac{(x-5)}{30}\\\\(x-5)=30\\\\x=30+5\\\\x=35\ ft$

So, the value of x is equal to 35 feet. The correct option is (c).

5 0

3 years ago

If all of the diagonals are drawn from a vertex of a hexagon, how many triangles are formed?

Elan Coil [88]

If we consider it as a combination problem, then we could calculate the how many combinations are there if we pick up three nodes out of six nodes, and then we have:
$C_{6}^{3}= \frac{6*5*4}{3*2*1} =20$
And the answer should be 20

5 0

3 years ago

Read 2 more answers

Plss help I will mark brainliest

ladessa [460]

Answer:

utv = 2x-57 = 41

stv = x = 49

Step-by-step explanation:

x+2x-57=90

3x=147

x=49

3 0

3 years ago

A meat inspector has randomly selected 30 packs of 95% lean beef. The sample resulted in a mean of 96.2% with a sample standard

kirza4 [7]

Answer:

a

The upper bound of the 99% prediction level is $98.2$

b

The 95% confidence interval is $9.7383 < \mu < 10.2617$

Step-by-step explanation:

Considering first question

From the question we are told that

The sample size is n = 30

The sample mean is $\= x = 96.2\%$

The standard deviation is $s = 0.8\%$

Generally the degree of freedom is mathematically represented as

$df = n - 1$

=> $df = 30 - 1$

=> $df = 29$

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the t distribution table the critical value of at a degree of freedom of is

$t_{\alpha , 29} = 2.462$

Generally the 99% prediction level is mathematically represented as

$\= x \pm [(t_{\alpha , df }) * s * (\sqrt{1 + \frac{1}{ n} } )}]$

Generally the upper bound of the 99% prediction level is mathematically represented as

$\= x + [(t_{\alpha , df }) * s * (\sqrt{1 + \frac{1}{ n} } )}]$

=> $96.2 + (2.462 ) * 0.8 * (\sqrt{1 + \frac{1}{ 30} } )}]$

=> $98.2$

Considering second question

Generally the sample is mathematically represented as

$\= x = \frac{\sum x_i}{n}$

=> $\= x = \frac{ 9.8 + 10.2 + \cdots +9.6 }{7}$

=> $\= x = 10$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{ \frac{ \sum ( x_ i - \= x)}{n-1} }$

=> $\sigma = \sqrt{ \frac{ ( 9.8 -10)^2 + ( 10.2 -10)^2 + \cdots + ( 9.6 -10)^2 }{7-1} }$

=> $\sigma = 0.283$

Generally the degree of freedom is mathematically represented as

$df = n- 1$

=> $df = 7- 1$

=> $df = 6$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the t distribution table the critical value of at a degree of freedom of is

$t_{\frac{\alpha }{2} , 6 } = 2.447$

Generally the margin of error is mathematically represented as

$E = t_{\frac{\alpha }{2} , 6 } * \frac{\sigma }{\sqrt{n} }$

=> $E =2.447* \frac{0.283 }{\sqrt{7} }$

=> $E =0.2617$

Generally 95% confidence interval is mathematically represented as

$\= x -E < \mu < \=x +E$

=> $10 -0.2617 < \mu < 10 + 0.2617$

=> $9.7383 < \mu < 10.2617$

7 0

3 years ago