The ratio, simplify it
12shirts:6jeans
12/6=2/1
or
2shirts:1jean
18shirts
18/2=9
2shirts times 9=18shirst
2shirts:1jean times 9:9=18shirts:9jeans
answer is 9 pairs of jeans
Answer:
Probably c
Step-by-step explanation:
Tbh
The quantity 5 more than a number t is labeled as (5+t)
Product of 9 and the quantity is labeled as = 9(5+t) which equals 45+9t
Result is less than 6 so the equation becomes
45+9t < 6
Option C: -3 is the average rate of change between
and 
Explanation:
The formula to determine the average rate of change is given by
Average rate of change = 
We need to find the average rate of change between
and 
Thus, from the table, we have,
, 
, 
Thus, substituting these values in the formula, we get,
Average rate of change = 


Thus, the average rate of change between
and
is -3.
Hence, Option C is the correct answer.
Answer: The team won 100 games and losses 28 games
Step-by-step explanation:
Let the number of games won denoted by x and the games lost is denoted by y .
Given : A minor league baseball team plays 128 games in a season.
Team won 16 more than three times as many games as they lost.
Then, the system of equations, we have

We can rewrite equation (2) as 
Now, Eliminate equation (3) from (1), we get

Substitute the value of y in (2), we get

Hence, the team won 100 games and losses 28 games.