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2 years ago

15. Apply Mathematics (1)(A) Suppose you have a box with a 4 X 4-in.

Mathematics

1 answer:

erastova [34]2 years ago

5 0

Answer:

Step-by-step explanation:

Formula for calculating the surface area of the box S = 2(LW+LH+WH) where

L is the length of the box

W is the width of the box

H is the height of the box

If the box is square based with dimension 4 * 4in, then L = W = 4in. substituting this values given into the formula we will have;

S = 2(4(4)+4H + 4H)

S = 2(16+8H)

S = 32+16H

Hence, The function that represents the surface area of this box as a

function of its height is S = 32+16H where H is the height of the box

Given H = 6.5in, to evaluate the function, we will substitute h = 6.5in into the modeled equation;

S = 32+16H

S = 32+16(6.5)

S = 32+106

S = 138in²

Hence the total surface area of the box is 138in²

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podryga [215]

Step-by-step explanation:

and and get some tonight at work today but it will take him home to a and then you can see to do with me for a bit of the time and

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3 years ago

Determine if the following system of equations has no solutions, infinitely many

DochEvi [55]

Answer:

There is one solution

Step-by-step explanation:

2x + y = -1

8x + 3y = -2

Multiply the first equation by -4

-8x -4y = 4

Then add the equations together to eliminate x

-8x -4y = 4

8x + 3y = -2

--------------------

-y = 2

Multiply by -1

y =-2

Now find x

2x+y =-1

2x+-2 =-1

Add 2 to each side

2x-2+2=-1+2

2x=1

Divide by 2

x = 1/2

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2 years ago

The circle graph shows how a family spends its annual income. If $26,450 is used for Auto and Entertainment combined, what is th

nika2105 [10]

12%+11%=23% so, $26,450/.23=$115,000.

5 0

3 years ago

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

4 0

3 years ago

A 13.5-m fire truck ladder is leaning against a wall. Find the distance d the ladder goes up the wall (above the fire truck)

larisa86 [58]

To solve this problem you must apply the proccedure shown below:

1. You have the the 13.5-m fire truck ladder is leaning against a wall and the ladder makes an angle of 39 degrees 45 ' with the horizontal.

2. Then you have:

39 degrees 45'=39.75°

Sin(39.75°)=d/13.5
d=13.5xSin(39.75°)
 d=8.63

8 0

3 years ago

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