Step-by-step explanation:
the answer is D
this is because, 24 + 9 = 33
and (3×8 + 3×3 =33)
So distribute using distributive property
a(b+c)=ab+ac so
split it up
(5x^2+4x-4)(4x^3-2x+6)=(5x^2)(4x^3-2x+6)+(4x)(4x^3-2x+6)+(-4)(4x^3-2x+6)=[(5x^2)(4x^3)+(5x^2)(-2x)+(5x^2)(6)]+[(4x)(4x^3)+(4x)(-2x)+(4x)(6)]+[(-4)(4x^3)+(-4)(-2x)+(-4)(6)]=(20x^5)+(-10x^3)+(30x^2)+(16x^4)+(-8x^2)+(24x)+(-16x^3)+(8x)+(-24)
group like terms
[20x^5]+[16x^4]+[-10x^3-16x^3]+[30x^2-8x^2]+[24x+8x]+[-24]=20x^5+16x^4-26x^3+22x^2+32x-24
the asnwer is 20x^5+16x^4-26x^3+22x^2+32x-24
Answer:
165km
Step-by-step explanation:
If Gina leaves now and drives at 66km/h she will reach Alton just in time for her appointment
Now:
Distance=Speed X Time
D=66 X t=66t.....(I)
If she leaves in 40 minutes,and she must get there at the same time, her new drive time will be:
t hours - 40 minutes
=(t-40/60)hours=( t-2/3) hours
Her Distance this time
D=90(t-2/3)=90t-60.....(ii)
Since the distance to Alton does not change, we equate (I) and (ii)
66t=90t-60
60=90t-66t
60=24t
t=2.5 hours
From equation (I)
Distance=66t=66X2.5=165km
Distance to Alton is 165km.
All of the answers are correct except the last one
