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Sindrei [870]
3 years ago
14

Can you help me solve the linear equation algebraically y=-x-3. y=-2x-8​

Mathematics
2 answers:
max2010maxim [7]3 years ago
7 0

Answer:

I can't it's to hard try studying

sesenic [268]3 years ago
5 0
Answer:
x=-5
y=2

Explanation:
Since both of these equations are equal to y, they have to be equal to each other. Set them equal to each other like this: -x-3= -2x-8. Multiply everything by negative 1 to get rid of the negative signs. The equation will look like this: x+3= 2x+8. Than subtract the x from both sides. Than subtract 8 from both sides. That should get you to x=-5. Than plug in -5 into the x value for one of the linear equations. It will get you 2 for the y.
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solution:

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X = √y²+z²

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7 0
3 years ago
P(t) = 8 - 2(squareroot)2t + 4
BartSMP [9]

Step-by-step explanation:

P(t) = 8 − 2√(2t + 4)

The x-intercept(s) is where t = 0.

P(0) = 8 − 2√(0 + 4)

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The y-intercept(s) is where P = 0.

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√(2t + 4) = 4

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2t = 12

t = 6

So the intercepts are at (0, 4) and (6, 0).

The easiest way to tell if the function is increasing or decreasing is to graph it.  Otherwise, we have to either use calculus to find the derivative, or assume the function is constantly increasing/decreasing and use limits.

lim(t→∞) P(t) = -∞

The function is decreasing.

6 0
3 years ago
I need to know the answer to this question
Daniel [21]
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3 years ago
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AURORKA [14]

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Step-by-step explanation:

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4 years ago
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olga2289 [7]

Answer:  

The Original Number is 36 :)

explanation:

4 0
3 years ago
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