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3 years ago

Show me the identity property of addition

Mathematics

2 answers:

Burka [1]3 years ago

6 0

Step-by-step explanation: The identity property holds true for addition. The statement 5 + 0 = 5 represents the identity property of addition.

The identity property of addition says that when we add 0 to any number, the sum is equal to the original number.

In general terms, we can write the identity property of addition as a + 0 = a where a is a variable that represents any number.

AfilCa [17]3 years ago

5 0

Example:a+b=b+a
ab=ba
(a+b)+c = a(b+c)

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A standard basketball court is a rectangle with the length 94 feet and width 50 feet. How much square feet or flooring would you

Lapatulllka [165]

Answer:

4700 ft

Step-by-step explanation:

Find the area (l x w)

94 x 50 = 4700 feet

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3 years ago

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Pls help me give u a brainlest

Snezhnost [94]

Answer:

2,139

Step-by-step explanation:

Volume= length X Width X Height

L= 15.5 cm

W= 9.2 cm

H= 15

L X W X H= ?

15.5 X 9.2 X 15=?

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3 years ago

Someone plz help meh 48 = 9x + 3 A) 5 B) -13 C) 8 D) -1

balandron [24]

The answer is A) 5

This is because:

9(5)+3
=45+3
= 48

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3 years ago

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What is the perimeter in square units of the rectangle shown on the coordinate grid?

Rashid [163]

In order to find the Perimeter of the Rectangle, First we need to find the Length and Width of the Rectangle.

Distance between two points (x₁ , y₁) and (x₂ , y₂) is given by :

$\bigstar\;\; \mathsf{Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}$

There are two lengths in a rectangle. Let us find any one length of the rectangle.

I'm considering the length with co-ordinates (-8 , 2) and (-2 , 10)

Here : x₁ = -8 and x₂ = -2 and y₁ = 2 and y₂ = 10

Substituting the values in the distance formula, We get :

$\mathsf{\implies Length = \sqrt{[-2 - (-8)]^2 + [10 - 2]^2}}$

$\mathsf{\implies Length = \sqrt{[-2 + 8]^2 + [8]^2}}$

$\mathsf{\implies Length = \sqrt{[6]^2 + [8]^2}}$

$\mathsf{\implies Length = \sqrt{36 + 64}}$

$\mathsf{\implies Length = \sqrt{100}}$

$\mathsf{\implies Length = 10}$

There are two widths in a rectangle. Let us find any one width of the rectangle.

I'm considering the width with co-ordinates (-2 , 10) and (2 , 7)

Here : x₁ = -2 and x₂ = 2 and y₁ = 10 and y₂ = 7

Substituting the values in the distance formula, We get :

$\mathsf{\implies Width = \sqrt{[2 - (-2)]^2 + [7 - 10]^2}}$

$\mathsf{\implies Width = \sqrt{[2 + 2]^2 + [-3]^2}}$

$\mathsf{\implies Width = \sqrt{[4]^2 + [-3]^2}}$

$\mathsf{\implies Width = \sqrt{16 + 9}}$

$\mathsf{\implies Width = \sqrt{25}}$

$\mathsf{\implies Width = 5}$

Perimeter of a Rectangle is given by : 2[Length + Width]

$:\implies$ Perimeter of the given rectangle = 2[10 + 5]

$:\implies$ Perimeter of the given rectangle = 2[15]

$:\implies$ Perimeter of the given rectangle = 30

Answer : Perimeter of the given rectangle is 30 square units

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3 years ago

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The length of a rectangle is 2 cm less than twice the width. The area of the rectangle is 112 cm2. Find the length and width of

ELEN [110]

Let breadth be x

Length=2x-2

We know

$\boxed{\sf Area=Length\times Breadth}$

$\\ \sf\longmapsto 112=x(2x-2)$

$\\ \sf\longmapsto 2x^2-2x-112=0$

$\\ \sf\longmapsto x=-7\:or\:x=8$

Ignore negative value

Now

$\\ \sf\longmapsto Length=2x-2=2(8)-2=16-2=14$

$\\ \sf\longmapsto Breadth=8$

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3 years ago