Given:
Equation of line
.
To find:
The equation of line that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.
Solution:
The given equation of line can be written as

Slope of line is



Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is


![[\because m_1=\dfrac{7}{4}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20m_1%3D%5Cdfrac%7B7%7D%7B4%7D%5D)
Now, the slope of perpendicular line is
and it goes through (-21,2). So, the equation of line is






Therefore, the required equation in slope intercept form is
.
Just as you would do it with any other number.
Write out some of it, then move the decimal point 3 places this way <=== .
Some of pi : 3.14159
Divide by 1,000 : 0.00314159
404,991
PEMDAS
Multiplication comes before subtraction
900x450=405,000
405,000-9=404,991
You need to use division.
Answer:
₹42,500
Step-by-step explanation:
Let Sonali's monthly income be ₹x
<h2>According to the question </h2>







So your answer will be ₹42,500.