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Dafna11 [192]
3 years ago
5

In the figure, m ǁ n, and s is a transversal that crosses the parallel lines.

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
3 0
The answer is angle 4 and angle 6 so B is correct.
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Solve : -0.375c - 11 = 13<br><br> please help me and thank youu :)
Sonja [21]
It would be: -0.375c - 11 = 13
-0.375c = 13 + 11
c = -24/0.375
c = -64

In short, Your Answer would be -64

Hope this helps!
3 0
3 years ago
Read 2 more answers
Sin - 22.5 degrees =
Studentka2010 [4]

Answer:

-0.38268343236 (or 0.382)

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How do you tell Side-side-side, Side-Angle-Side, Angle-Angle-Side apart?
Rainbow [258]
They all have abbreviations: Side-Side-Side (SSS), Side-Angle-Side (SAS) and Angle-Angle-Side (AAS). 
7 0
3 years ago
Point b has coordinates (3,-4) and lies on the circle whose equation is x^2 + y^2= 25. If angle is drawn in a standard position
lakkis [162]
<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
</span>
<span>BO^2=AO^2+AB^2 \\ BO^2=3^2+4^2  \\ BO^2=9+16  \\ BO^2=25  \\ BO=5.
</span>
{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>
\sin \angle BOA= \dfrac{AB}{BO} = \dfrac{4}{5} =0.8

Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
<span /><span>
</span><span>
</span>\sin \theta=-0.8 .





3 0
3 years ago
Write an algebraic expression that models the word phrase "the product of 8 and the sum of a number X and 3"
Leya [2.2K]
The answer is d.
8(x+3)
4 0
3 years ago
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