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Andreyy89
3 years ago
5

8.

Mathematics
2 answers:
Anettt [7]3 years ago
8 0
Pay is 5.75 per hour
11.50/2=5.75
23.00/4=5.75
34.50/6=5.75
46.00/8=5.75
p=5.75h
Answer is: D
DiKsa [7]3 years ago
5 0

Answer:

D. p = 5.75h

Step-by-step explanation:

the answer is C) p= 5.75h

...................................................................................................................................................

Answer:

p = 5.75h

Step-by-step explanation:

The variable p (Pay) increases as a function of 5.75 for each h (hour worked).

You can see it when you apply each value given to the function p = 5.75h knowing that h = {2, 4, 6, 8} and p = {11.50, 23.00, 34.50, 46.00}

Substituting each value of "h" in the equation of the function you can corroborate it,

For h = 2, p = 5.75 (2) = 11.50

For h = 4, p = 5.75 (4) = 23.00

For h = 6, p = 5.75 (6) = 34.50

For h = 8, p = 5.75 (8) = 46.00

So, the answer is p = 5.75h

I hope this helps!

...............................................................................................................................................

answer is C. p=5.75h

if h = 2 then p = 5.75 x 2 = $11.50

if h = 4 then p = 5.75 x 4 = $23.00

if h = 6 then p = 5.75 x 6 = $34.50

if h = 8 then p = 5.75 x 8 = $46.00

...............................................................................................................................................

maddymcg408

Virtuoso

252 answers

3.8K people helped

Answer:

I'm gonna go with p = 5.75h

Step-by-step explanation:

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2 years ago
A carpentry shop currently sells 66000 decoy ducks per year at a cost of 16 dollars each. In the previous year when they raised
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Answer:

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Step-by-step explanation:

<h2>Buckle up! This is a good one!</h2>

First we have to find the line that goes trough the two points. And it has the form :

y=mx+b

<em>m is often called the slope.</em>

Given the two points (66000, 16) and (51000, 21) we find m with this formula:

m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }\\m=\frac{21-16}{51000-66000} \\m=-\frac{5}{15000} \\m=-\frac{1}{3000}

We pick the point (51000,21) and plug it into the equation of the line and we find b:

y= mx + b\\21=(-\frac{1}{3000} )(51000)+b\\21=-17+b\\21+17=b=38

<h3>And we have got our line equation</h3>

y= -\frac{1}{3000}x + 38\\

<u>Where x represents the quantity and y represents the price.</u>

<u />

<h2>The revenue</h2>

The revenue is price times quantity, since price is y and quantity is x, we get

y=-\frac{1}{3000} x+38\\y*x=x*(-\frac{1}{3000} x+38)\\yx=-\frac{1}{3000} x^2+38x\\R(x)=-\frac{1}{3000} x^2+38x

<h3>to maximize the revenue, we get the first derivative:</h3>

R(x)=-\frac{1}{3000} x^2+38x\\R'(x)=-(2)\frac{1}{3000} x+38\\R'(x)=-\frac{2}{3000} x+38\\\\R'(x)=-\frac{1}{1500} x+38\\\\

<h3>and we make R'(x)=0:</h3>

R'(x)=-\frac{1}{1500} x+38=0\\38=\frac{1}{1500} x\\38*1500=x=57000

So the quantity that maximizes revenue is 57000,

<h3>let's find out the price by plugging it into the equation:</h3>

y= -\frac{1}{3000}x + 38\\y= -\frac{1}{3000}(57000) + 38\\y= -19 + 38\\y=19

<h2>And there you go! 19 dollars is the price the carpentry shop should charge per decoy duck.</h2>
7 0
3 years ago
Which is the largest interval over which the function in the table is increasing?
Levart [38]

Answer:

Solution given:

y=-1/2 x²

for

f(x)=-1/2 x².

differentiating each term with respect to x

f'(x)=-x

when

x=-4

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when

x=-2

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when x=0

f'(0)=0 stationary point.

other points are decreasing

so

largest interval of increasing is

A.X<-2

6 0
3 years ago
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