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3 years ago

Write an example of an algebraic expression that has a nonnegative value regardless of the variable

2 answers:

6 0

it could be (8x+3,72-9x²⁰¹⁷)⁸+3 or just simply x²

it is always greater or equal 0, for any x∈R

"Non nobis Domine, non nobis, sed Nomini tuo da gloriam."

Regards M.Y.

yuradex [85]3 years ago

4 0

X²

If the value is positive, the result will be positive, if the value is negative, the result will be positive. Also x * x, or x^4, etc.

You might be interested in

A line has a slope of zero and passes through the point (-2, 3). Which of the following points must also lie on the line?

brilliants [131]

Answer:

(5,3)

Step-by-step explanation

Because the slope is 0, it means its a horizontal line. because the horizontal is on 3, then it doesnt matter what x is as long as y is 3 if that makes any sense.

7 0

3 years ago

A fair die is rolled 12 times. the number of times an even number occurs on the 12 rolls has

bonufazy [111]

Answer:

Step-by-step explanation:

For a fair die, there are six likely options; 1, 2, 3, 4, 5, and 6

the probability of a even number is 3/6 = 0.5

Since the results of the die roll is independent and each trial is mutually exclusive, the distribution to explain the probability of occurrence will follow a binomial distribution such that n is the number of trials

x = number of successful throws

therefore for a Binomial distribution where

P(X =x) = nCx . P^x . (1-P)^ (n-x)

since p = 0.5, and n = 12, the distribution follows

P(X = x) = 12Cx . 0.5^x . (1 - 0.5)^(12- x)

= 12Cx . 0.5^x . 0.5)^(12- x)

where x = (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)

since we are interested in the probability of the number of times an even number occurs

it can occur either as P(X = 0), P(X =1), P(X =2), P(X =3), P(X =4), P(X =5), P(X =6), P(X =7), P(X =8), P(X =9), P(X =10), P(X =11), and P(X =12)

For no even number in 12 rolls,

P(X = 0) = 12C0 . 0.5^0 . 0.5^(12- 0) = 0.000244

For one even number in 12 rolls,

P(X = 1) = 12C1 . 0.5^1 . 0.5^(12- 1) = 0.002930

For two even number in 12 rolls,

P(X = 2) = 12C2 . 0.5^2 . 0.5^(12- 2) = 0.016113

For three even number in 12 rolls,

P(X = 3) = 12C3 . 0.5^3 . 0.5^(12- 3) = 0.053711

For four even number in 12 rolls,

P(X = 4) = 12C4 . 0.5^4 . 0.5^(12- 4) = 0.120850

For five even number in 12 rolls,

P(X = 5) = 12C5 . 0.5^5 . 0.5^(12- 5) = 0.193359

For six even number in 12 rolls,

P(X = 6) = 12C6 . 0.5^6 . 0.5^(12- 6) = 0.225586

For seven even number in 12 rolls,

P(X = 7) = 12C7 . 0.5^7 . 0.5^(12- 7) = 0.193359

For eight even number in 12 rolls,

P(X = 8) = 12C8 . 0.5^8 . 0.5^(12- 8) = 0.120850

For nine even number in 12 rolls,

P(X = 9) = 12C9 . 0.5^9 . 0.5^(12- 9) = 0.053711

For ten even number in 12 rolls,

P(X = 10) = 12C10 . 0.5^10 . 0.5^(12- 10) = 0.016113

For eleven even number in 12 rolls,

P(X = 11) = 12C11 . 0.5^11 . 0.5^(12- 11) = 0.002930

For twelve even number in 12 rolls,

P(X = 12) = 12C12 . 0.5^12 . 0.5^(12- 12) = 0.000244

Final test summation[P(X)] = 1

i.e.

P(X = 0) + P(X =1) + P(X =2) + P(X =3) + P(X =4) + P(X =5) + P(X =6) + P(X =7) + P(X =8) + P(X =9) + P(X =10) + P(X =11) + P(X =12) = 1

Hence since 0.000244 + 0.002930 + 0.016113 + 0.053711 + 0.120850 + 0.193359 + 0.225586 + 0.193359 + 0.120850 + 0.053711 + 0.016113 + 0.002930 + 0.000244 = 1.000000,

the probability value stands

7 0

3 years ago

20 points pls help imp

Gnom [1K]

180 - 79
101 degrees is the answer

6 0

3 years ago

Read 2 more answers

How do I simplify these expressions? 5(x+8)+3 3.6x-7-5.1x 4+8x+2.2-10x

Aleks04 [339]

Answer:

1. 5x +43

2. -1.5x - 7

3. 6.2 - 2x

Step-by-step explanation:

Equation 1:

5 (x+8) +3

First, we can distribute the 5 to the (x+8) and get 5x + 40. Distributing is when we multiply the 5 by the first number (x) and then by the second number (8) Because they aren't like terms (don't both have x's) we cannot combine then and must keep them separated by a subtraction sign

Now we have: 5x + 40 + 3

Next, we can combine the like terms. This means that any that have the same variable can be combined. So, the 5x has no other x's so he has to stay how he is. The 40 and the 3, however, can be added together to get 43.

Our finished equation is: 5x + 43

Equation 2:

3.6x - 7 - 5.1x

First, we can combine like terms as we learned in the last problem. This would be our x's since we have multiple.

We can add 3.6x and -5.1x and get -1.5x

Now we have: -1.5x - 7

Equation 3:

4 + 8x + 2.2 - 10x

We can start with either the numbers with x's or without but I'll just do the x's. So we have 8x and -10x. Adding these together would get us -2x.

Next, we can combine 4 and 2.2 and get 6.2.

Now, putting these back into our equation would look like this:

6.2 - 2x

I'm not sure how much my explanations helped, but I hope you understand!!

8 0

3 years ago

Please visit my previous questions to know what the word problem is

Rudiy27

Answer:

As below

Step-by-step explanation:

using eq from problem 4) y = -45x + 1080

then use the point slope formula with the slope of the above line at -45 and plug in your given point of (8, 240)

y-y1 = m(x-x1) where m is the slope above

y-240 = -45 (x - 8 ) this is an equation for the line but the teacher probably wants the slope intercept form... the formula is y = mx + b

soooo...

y-240 = -45x + 360

y = -45x +360 + 280

y = -45x + 640

there you go :)

4 0

3 years ago