The answer would be 4 divided by 2/3 = 6 tiles
One function you would be trying to minimize is
<span>f(x, y, z) = d² = (x - 4)² + y² + (z + 5)² </span>
<span>Your values for x, y, z, and λ would be correct, but </span>
<span>d² = (20/3 - 4)² + (8/3)² + (-7/3 + 5)² </span>
<span>d² = (8/3)² + (8/3)² + (8/3)² </span>
<span>d² = 64/3 </span>
<span>d = 8/sqrt(3) = 8sqrt(3)/3</span>
Answer:
Step-by-step explanation:
-(26) - 3y = 4
-3y = 30
y = -10
Answer:

Step-by-step explanation:
Given
The attached rhombus
Required
The area
First, calculate the length of half the vertical diagonal (x).
Length x is represented as the adjacent to 60 degrees
So, we have:

Solve for x


So:


At this point, we have established that the rhombus is made up 4 triangles of the following dimensions


So, the area of the rhombus is 4 times the area of 1 triangle



