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My name is Ann [436]
3 years ago
14

Can someone please help me with these questions!!!!

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer: B

Step-by-step explanation:

The only labeled angle is 111

We can conclude that angle 3 is also 111

1 and 2 are both less than 90

Therefore, 1 is 69, 2 is 69, and 3 is 111

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3 turtles walking.
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Answer:

Divide 250 by 9.4 to get 26.6

Step-by-step explanation:

To calculate her unit rate, 1 minute, we must divide the distance travelled over 9.4 minutes by 9.4 to see how far she travelled in 1 minute.

8 0
3 years ago
The equations x + 5 y = 10, 3 x minus y = 1, x minus 5 y = 10, and 3 x + y = 1 are shown on the graph below. On a coordinate pla
nadezda [96]

Answer:

A: (–0.3, 2.1)

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3 years ago
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If a smoothie recipe calls for 8 pints of mango juice but only 10 cups of mango juice are available, what is the scaling factor
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4 years ago
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Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species
kotegsom [21]

Answer:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

Step-by-step explanation:

The logistic equation is the following one:

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that P(0) = 80, K = 2000.

The number of fish tripled in the first year. This means that P(1) = 3P(0) = 3(80) = 240.

Using the equation for P(1), that is, P(t) when t = 1, we find the value of r.

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}

280*(2000 + 80(e^{r} - 1)) = 160000e^{r}

280*(2000 + 80e^{r} - 80) = 160000e^{r}

280*(1920 + 80e^{r}) = 160000e^{r}

537600 + 22400e^{r} = 160000e^{r}

137600e^{r} = 537600

e^{r} = \frac{537600}{137600}

e^{r} = 3.91

Applying ln to both sides.

\ln{e^{r}} = \ln{3.91}

r = 1.36

This means that the expression for the size of the population after t years is:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

4 0
3 years ago
Please help and explain please. would appreciate it!
Reptile [31]

Answer:

Step-by-step explanation:

A/4=72/12

A=4(72)/12

A=24 u^2

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3 years ago
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