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Natasha_Volkova [10]
3 years ago
14

What is an equation of a line with the given slope and y-intercept. m = 2, b = 6

Mathematics
1 answer:
Schach [20]3 years ago
5 0

Answer:

Slope intercept form is y=2x+b

Step-by-step explanation:

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Find the value of x<br> 12<br> 5<br> X
steposvetlana [31]

Answer:

x = 13

Step-by-step explanation:

Note that the side length x is opposite of the right angle, which means that it is the hypotenuse, which will usually be denoted as c.

Set the equation:

a² + b² = c²

let:

a = 5

b = 12

c = x

Plug in the corresponding numbers (& x) to the corresponding variables:

(5)² + (12)² = (x)²

Simplify. First, solve for the power, and then add:

x² = (5²) + (12²)

x² = (5 * 5) + (12 * 12)

x² = 25 + 144

x² =  169

Next, root both sides of the equation:

√x² = √169

x = √169 = √(13 * 13) = 13

x = 13

~

Note the rules, and it should be easier:

30-60-90° = 1 , √3 , 2

45-45-90° = 1 , 1 , √2

Any other measurements use the equation:  a² + b² = c²

5 0
2 years ago
Please awnser for brainlyest awnser btw I don’t like emojis ✌️✌️✌️✌️✌️✌️✌️
nexus9112 [7]

Answer:

7. Mean = 48

Median = 47.5

Mode = 72

Range = 66

8. Mean= 59.625

Median = 61

Mode = 90

Range = 79

9. Mean = 31.57

Median = 32

Mode = 46

Range = 34

10. Mean = 42.11

Median = 36

Mode = 51

Range = 51

Step-by-step explanation:

Mean is the average. Mode is the number that appears the most. Median is the middle number. Range is the biggest number minus the smallest number.

Hope this helps.

3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
2 years ago
In which quadrant does the ordered pair (5, -6) lie?
guajiro [1.7K]
The coordinate (5,-6) lies in the fourth coordinate, because the first is x positive y positive, the second is x negative and y positive, the third is x negative and y negative, and the fourth is x positive y negative. This is x positive y negative, so it is in the fourth quadrant.
5 0
3 years ago
Read 2 more answers
Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7
rosijanka [135]
\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx

Notice that x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1). Decompose the integrand into partial fractions:

\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}
=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}

Integrating term-by-term, you get

\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx
=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C
5 0
3 years ago
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