Answer: 9.08 L
Explanation:
To calculate the moles :
According to stoichiometry :
4 moles of require = 3 moles of
Thus 0.54 moles of will require=
of
Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atm respectively.
According to the ideal gas equation:
P = Pressure of the gas = 1 atm
V= Volume of the gas = ?
T= Temperature of the gas = 273 K
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas= 0.405
Thus 9.08 L of at STP would be required