How to get 1m solution to 0.001m solution?

What are digital and analog signals in real life? 20 PTS!

rusak2 [61]

Answer:

Analog signal is a continuous signal which represents physical measurements. Digital signals are discrete time signals generated by digital modulation. Human voice in air, analog electronic devices. Computers, CDs, DVDs, and other digital electronic devices.

Explanation:

8 0

3 years ago

g The following equation is given for the dissociation of the complex ion Ag(NH3) 2. The dissociation constant, Kd, is the equil

Sveta_85 [38]

Answer:

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

Explanation:

Let's consider the dissociation reaction of the complex ion Ag(NH₃)₂⁺.

Ag(NH₃)₂⁺(aq) ⇄ Ag⁺(aq) + 2 NH₃(aq)

The dissociation constant, Kd, is the equilibrium constant for the dissociation of the complex ion, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.

The dissociation constant for this reaction is:

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

8 0

3 years ago

What is the formula for aluminum oxide

Romashka [77]

The formula is AI203

4 0

4 years ago

Read 2 more answers

How many protons, electrons, and neutrons does an atom with atomic number 50 and a mass number of 125 contain?

EleoNora [17]

Answer:

a) 50 protons, 50 electrons, 75 neutrons

Explanation:

How many protons, electrons, and neutrons does an atom with atomic number 50 and a mass number of 125 contain?

a) 50 protons, 50 electrons, 75 trons

b) 75 electrons, 50 protons, 50 neutrons

c) 120 neutrons, 50 protons, 75 electrons

atomic number IS the number of protons

atomic mass IS the total of protons + neutrons

so 50 protons

125-50 = 75 neutrons

in a neutral atom,

number of negative electrons = number of positive protons

a) 50 protons, 50 electrons, 75 neutrons

3 0

3 years ago

A buffer solution contains 0.496 M KHCO3 and 0.340 M K2CO3. If 0.0585 moles of potassium hydroxide are added to 250. mL of this

aev [14]

Answer:

pH = 10.9

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to say that the undergoing reaction between this buffer and OH⁻ promotes the formation of more CO₃²⁻ because it acts as the base, we can do the following:

$n_{CO_3^{2-}}=0.34mol/L*0.250L+0.0585mol=0.1435mol\\\\n_{HCO_3^{-}}=0.34mol/L*0.250L-0.0585mol=0.0265mol$

The resulting concentrations are:

$[CO_3^{2-}]=\frac{0.1435mol}{0.25L}=0.574M \\$

$[HCO_3^{-}]=\frac{0.0265mol}{0.25L}=0.106M$

Thus, since the pKa of this buffer system is 10.2, the change in the pH would be:

$pH=10.2+log(\frac{0.574M}{0.106M} )\\\\pH=10.9$

Which makes sense since basic OH⁻ ions were added.

Regards!

6 0

4 years ago