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egoroff_w [7]
2 years ago
9

How much sucrose can dissolve in 200g of water at 70 °C?​

Chemistry
2 answers:
Naya [18.7K]2 years ago
8 0
Answer: The solubility of sucrose in water at 70o C is 320 g per 100 g of water.
valentinak56 [21]2 years ago
6 0
Is 320 g per 100 g of water.
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Why would an organism utilize alcohol fermentation if it is wasteful of the energy in food molecules and poses a threat of death
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All of the choices are real advantages of alcohol fermentation - E)

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A chemistry student needs 30,0 mL of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the stu
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Answer:

1.878g

Explanation:

Volume = 30.0ml

Density = 0.626gcm−3

Mass = ?

Be careful in this kind of questions to check for the units. In this case one has to remember 1 mL equal 1 cm³ so density = 0.626g/ml

The relationship between all three parameters is given by the equationn below;

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A proton is a subatomic particle carrying a charge equal to but opposite that of an electron
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True

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3 years ago
Consider the mixture of ethanol, c2h5oh, and o2. how many molecules of co2, h2o, c2h5oh, and o2 will be present if the reaction
Natali [406]

The reaction between ethanol and oxygen must be a combustion reaction to give carbon dioxide and water as products.

The reaction between ethanol, C_2H_5OH and oxygen, O_2 is as follows:

C_2H_5OH+O_2\rightarrow CO_2+H_2O

In order to balance the reaction (the number of atoms of each element in the reaction are same on both the sides that is product and reactant),  O_2 is multiplied by 3 in the reactant side and CO_2 is multiplied by 2 and H_2O is multiplied by 3 on product side.

So, the balanced reaction is:

C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O

From the balanced reaction it is clear that 1 mole of C_2H_5OH reacts with 3 moles of O_2 to give 2 moles of CO_2 and 3 moles of H_2O.

Since, 1 mole = 6.022\times 10^{23} molecules (Avogadro's number)

So,

Number of molecules of C_2H_5OH = 6.022\times 10^{23} molecules.

Number of molecules of O_2 = 6.022\times 10^{23}\times 3 = 18.066\times 10^{23} molecules.

Number of molecules of CO_2 = 6.022\times 10^{23}\times 2 = 12.044\times 10^{23} molecules.

Number of molecules of H_2O = 6.022\times 10^{23}\times 3 = 18.066\times 10^{23} molecules.

3 0
3 years ago
Read 2 more answers
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