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salantis [7]
3 years ago
9

A family plans to have 3 children. For each birth, assume that the probability of a boy is the same as the probability of a girl

. What is the probability that they will have at least one boy and at least one girl?
a. 0.5
b. 0.125
c. 0.75
d. 0.875
e. None of these
Mathematics
1 answer:
Ugo [173]3 years ago
6 0

Answer:

c. 0.75

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

We have the following sample space

That is, the possible outcomes.

I am going to call boys b and girls g

b - b - b

b - b - g

b - g - b

b - g - g

g - b - b

g - b - g

g - g - b

g - g - g

Total outcomes:

8 outcomes

What is the probability that they will have at least one boy and at least one girl?

Desired outcomes:

At least one boy and at least one girl

b - b - g

b - g - b

b - g - g

g - b - b

g - b - g

g - g - b

Six desired outcomes.

Probability

P = \frac{6}{8} = 0.75

The correct answer is:

c. 0.75

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<em>The coordinates of the 4th point is (-2,3)</em>

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A and B have the same y-coordinates, while their x-coordinates are additive inverse

This means that:

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