Answer:
the area is 11.46
Step-by-step explanation:
i hope this helps
Answer:
x < - 4
Step-by-step explanation:
- 5 - 3x > 2(10 + 2x) + 3 ← distribute parenthesis and simplify right side
- 5 - 3x > 20 + 4x + 3
- 5 - 3x > 4x + 23 ( add 3x to both sides )
- 5 > 7x + 23 ( subtract 23 from both sides )
- 28 > 7x ( divide both sides by 7 )
- 4 > x , that is
x < - 4
Answer:
The answer is 0.2mile
Step-by-step explanation:
The vertical height of the building, which is 630ft, is opposite the angle of elevation (30°).
While the horizontal distance to the tower is adjacent to the building. So, we take the tangent of the angle of elevation in terms of this unknown distance (x) and the vertical height.
So,
Tangent = opposite ÷ adjacent
Tan30° = 630ft ÷ x
x = 630ft ÷ tan30°
x = 1091.192ft
But,
1 mile = 5,280ft
1091.192ft = (1/5280) x 1091.192
= 0.2mile
Yes it is possible. Consider the following scenarios
Scenario A:
Min = 5
Q1 = 10
Median = 12
Q3 = 18
Max = 22
The IQR is equal to the difference of Q3 and Q1
IQR = Q3-Q1 = 18-10 = 8
The range is the difference of the min and max
Range = Max - Min = 22 - 5 = 17
So in summary for scenario A, we have
IQR = 8
Range = 17
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Now consider another scenario, call it scenario B, where
Min = 100
Q1 = 102
Median = 105
Q3 = 110
Max = 117
I claim that the IQR and Range for scenario B is going to be the same as in Scenario A. Let's find out
IQR = Q3 - Q1 = 110 - 102 = 8
Range = Max - Min = 117 - 100 = 17
So
IQR = 8
Range = 17
which is identical to scenario A.
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Scenario B has completely different data than scenario A, yet the IQR and Range are equal to scenario A's counterparts. This shows that it is possible to have 2 completely sets of data yet have the same IQR and range.
The wrap up here, and the answer to the question, is "yes it is possible" with the explanation given above.
The atmospheric pressure is 14 lb/s^2 at sea level is the answer.