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AlexFokin [52]
3 years ago
15

A basketball team played six games. In those games, the team won by 9 points, lost by 18, won by

Mathematics
1 answer:
Maksim231197 [3]3 years ago
7 0

Answer: 2

Step-by-step explanation:

From the question, we are informed that a basketball team played six games and that in those games, the team won by 9 points, lost by 18, won by 8, won by 11, lost by 3, and won by 5.

Thee mean difference in game scores over the six games will be calculated as the summation of the scores divided by 6. This. Will be:

= [9 + (-18) + 8 + 11 + (-3) + 5]/6

= 12/6

= 2

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Answer:

x = 18

Step-by-step explanation:

the sum of any exterior angle is equal to the sum of any two interior angles

3x-11 + 5x+14 = 9x-15

8x + 3 = 9x - 15

3 = x - 15

x = 18

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3 years ago
State what additional information is required in order to know that the triangles are congruent by AAS. part 2
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Answer:

Step-by-step explanation:

The trick is to find the third angle

180 - A - <BCA = <CBA

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Now by a little slight of hand, you get the two triangles to be equal by ASA, which always works.

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Tina's gross pay is $2680. How much of her gross pay will be deducted for FICA taxes?
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2 years ago
Which equation has the solutions x=1+or-square root of 5?
stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> x^{2}+2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=-4+1

x^{2}+2x+1=-3

Rewrite as perfect squares

(x+1)^{2}=-3

(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i

therefore

case a) is not the solution of the problem

<u>case b)</u> x^{2}-2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=-4+1

x^{2}-2x+1=-3

Rewrite as perfect squares

(x-1)^{2}=-3

(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i

therefore

case b) is not the solution of the problem

<u>case c)</u> x^{2}+2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=4+1

x^{2}+2x+1=5

Rewrite as perfect squares

(x+1)^{2}=5

(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}

therefore

case c) is not the solution of the problem

<u>case d)</u> x^{2}-2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=4+1

x^{2}-2x+1=5

Rewrite as perfect squares

(x-1)^{2}=5

(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

x^{2}-2x-4=0

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