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Usimov [2.4K]
3 years ago
10

What is a correct congruence statement for the triangles shown? Enter your answer in the box. ​ △QDJ≅△ ​ A triangle Q D J. The b

ase D J is horizontal and side Q D is vertical. Another triangle M C W is made. The base C W and side M C are neither horizontal nor vertical. Triangle M C W is to the right of triangle Q D J. The sides Q D and M C are labeled with a single tick mark. The sides D J and C W are labeled with a double tick mark. The sides Q J and M W are labeled with a triple tick mark.

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
7 0

Answer:

MCW

Step-by-step explanation:

almond37 [142]3 years ago
4 0

Answer: The correct congruence statement is \triangle QDJ\cong \triangle MCW.

Explanation:

It is given that A triangle Q D J. The base D J is horizontal and side Q D is vertical. Another triangle M C W is made. The base C W and side M C are neither horizontal nor vertical. Triangle M C W is to the right of triangle Q D J.

The sides Q D and M C are labeled with a single tick mark. The sides D J and C W are labeled with a double tick mark. The sides Q J and M W are labeled with a triple tick mark.

Draw two triangles according to the given information.

From the figure it is noticed that

QD\cong MC

DJ\cong CW

QJ\cong MW

So by SSS rule of congruence we can say that \triangle QDJ\cong \triangle MCW.

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Given that 1 kilogram weighs approximately 22 pounds, rewrite 10 pounds as an equivalent number of kilograms
yaroslaw [1]

Answer:

0.4545 kgs.

Step-by-step explanation:

Given that 1 kg weighs approximately 22 pounds.

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We can use this to convert lbs into kg.

22 lbs = 1 kg

Hence 1 lb = 1/22 = 0.04545 kg

Now to find out the equivalent weight for 10lbs,

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Hence 10 lbs = 10(0.04545) = 0.4545 kgs

Hence 10 pounds written in equivalent kgs would be0.4545 kgs.

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3 years ago
Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{k}{2s^2}

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Hope this helps!
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What is wrong in this
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Answer:

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Step-by-step explanation:

Simplifying

V = (20 + -2x)(15 + -2x)(x)

Reorder the terms for easier multiplication:

V = x(20 + -2x)(15 + -2x)

Multiply (20 + -2x) * (15 + -2x)

V = x(20(15 + -2x) + -2x * (15 + -2x))

V = x((15 * 20 + -2x * 20) + -2x * (15 + -2x))

V = x((300 + -40x) + -2x * (15 + -2x))

V = x(300 + -40x + (15 * -2x + -2x * -2x))

V = x(300 + -40x + (-30x + 4x2))

Combine like terms: -40x + -30x = -70x

V = x(300 + -70x + 4x2)

V = (300 * x + -70x * x + 4x2 * x)

V = (300x + -70x2 + 4x3)

Solving

V = 300x + -70x2 + 4x3

Solving for variable 'V'.

Move all terms containing V to the left, all other terms to the right.

Simplifying

V = 300x + -70x2 + 4x3

6 0
3 years ago
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