What is a correct congruence statement for the triangles shown? Enter your answer in the box. △QDJ≅△ A triangle Q D J. The b
ase D J is horizontal and side Q D is vertical. Another triangle M C W is made. The base C W and side M C are neither horizontal nor vertical. Triangle M C W is to the right of triangle Q D J. The sides Q D and M C are labeled with a single tick mark. The sides D J and C W are labeled with a double tick mark. The sides Q J and M W are labeled with a triple tick mark.
2 answers:
Answer: The correct congruence statement is .
Explanation:
It is given that A triangle Q D J. The base D J is horizontal and side Q D is vertical. Another triangle M C W is made. The base C W and side M C are neither horizontal nor vertical. Triangle M C W is to the right of triangle Q D J.
The sides Q D and M C are labeled with a single tick mark. The sides D J and C W are labeled with a double tick mark. The sides Q J and M W are labeled with a triple tick mark.
Draw two triangles according to the given information.
From the figure it is noticed that
So by SSS rule of congruence we can say that .
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<h2>Answer explanation:</h2>
If a coin is fair then it has two faces , one is heads and the another is tails.
The probability getting any favorable outcomes is given by the formula :-
So the factor effecting probability is just the number of favorable outcomes and total outcomes.
If a coin is tossed then the probability of getting heads will be :-
To get heads always this should be 1 , which can be happen if number of favorable outcomes is equal to total outcomes.
i.e. Number of heads = Number of total outcomes, this means coin should be biased.
Catching the coin in mid-air can never be a factor for this.
Therefore, the little brother's theory is false.