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2 years ago

PLZ IN NEED OF HELP

Mathematics

2 answers:

Serga [27]2 years ago

6 0

The roots would be x=-5 and x=-4 but with that website you just do -5 and -4

S_A_V [24]2 years ago

5 0

X=-5,-4 hope this helps!

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If one jar of peanut butter weights 1.6 pounds, how much does 5 jars of peanut butter weight?

Lady_Fox [76]

Answer:

5 × 1.6 = 8. The answer is 8 pounds.

Step-by-step explanation:

If you multiply 5 and 1.6, you get 8.

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3 years ago

Read 2 more answers

If the demand function for a commodity is given by the equation

Jet001 [13]

Answer:

q=26.92 p=31.13

Step-by-step explanation:

$p^{2} +16q=1400\\\\q=\frac{1400-p^{2} }{16} ;\\\\700-p^{2} +10q=0\\\\q=\frac{p^{2}-700 }{10} ;\\\\$

$q=q\\\\\frac{1400-p^{2} }{16} =\frac{p^{2}-700 }{10} \\\\10(1400-p^{2})=16(p^{2}-700)\\\\14000-10p^{2}=16p^{2}-11200\\\\14000+11200=16p^{2}+10p^{2}\\\\25200=26p^{2}\\\\p^{2}=\frac{25200}{26} \\\\p=+\sqrt{\frac{25200}{26}} \\\\p=31.13$

replace p in any equation and

$q=\frac{1400-p^{2} }{16} \\\\q=\frac{1400-(31.13)^{2} }{16}\\\\q=26.92$

3 0

3 years ago

Find all the roots of the equation x4 - 2x3 + 14x2 - 18x + 45 = 0 given that 1 + 2i is one of its roots.

patriot [66]

Asked and answered elsewhere.
brainly.com/question/10192511

Knowing that 1+2i is a root, you also know that 1-2i is a root, so one quadratic factor is
(x -1)² -(2i)² = x^2 -2x +5

Long division of the given polynomial by this quadratic gives a quotient of
x² +9
which has roots ±3i.

Then all the roots are {-3i, 3i, 1-2i, 1+2i}.

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3 years ago

Jason gets very nervous giving speeches in front of big crowds how can he combat his nervousness

gregori [183]

Answer: Jason can imagine everyone naked while on the stage, it will make him smile, and feel free.

Step-by-step explanation: I'ts pretty easy actually.

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2 years ago

. Andrew made an error in determining the polynomial equation of smallest degree whose roots are 3, 2+2i

KIM [24]

Answer:

Error of Andrew: Made incorrect factors from the roots

Step-by-step explanation:

Roots of the polynomial are: 3, 2 + 2i, 2 - 2i. According to the factor theorem, if a is a root of the polynomial P(x), then (x - a) is a factor of P(x). According to this definition:

(x - 3) , (x - (2 + 2i)) , (x - (2 - 2i)) are factors of the required polynomial.

Simplifying the brackets, we get:

(x - 3), (x - 2 - 2i), (x - 2 + 2i) are factors of the required polynomial.

This is the step where Andrew made the error. The factors will always be of the form (x - a) , not (x + a). Andrew wrote the complex factors in form of (x + a) which resulted in the wrong answer.

So, the polynomial would be:

$(x - 3)(x - 2 - 2i)(x - 2+2i)=0\\\\ (x-3)(x^{2}-2x+2xi-2x+4-4i-2xi+4i-4i^{2})=0\\\\ (x-3)(x^{2}-4x+4+4)=0\\\\ (x-3)(x^{2}-4x+8)=0\\\\ x^{3}-4x^{2}+8x-3x^{2}+12x-24=0\\\\ x^{3}-7x^{2}+20x-24=0$

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3 years ago