1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stepladder [879]
3 years ago
10

A square inch is the area covered by a square whose sides are 1 inch long. true or false?

Mathematics
2 answers:
marissa [1.9K]3 years ago
6 0

Answer:

True

Step-by-step explanation:

Because a square inch side measures an inch each! :D

iragen [17]3 years ago
4 0

Answer:

True

Step-by-step explanation:

You might be interested in
Which of the following is the last step in creating a budget?
pentagon [3]
If you list the answer choices, I might be able to help you better.
8 0
2 years ago
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
2 years ago
7.Suppose that water is entering a cylindrical water tank so that the initial height of the water is 3 cm and the
lukranit [14]

Answer:

H(t) = 3*2^{t/30}

Step-by-step explanation:

Height doubles at every 30 seconds, so let's call n how many times it happens, and the t the total time:

n = t/30

If the height doubles one time, it is multiplied by 2, if it doubles 2 times, it's multiplied by 2², for n times, it is multiplied by 2ⁿ, so for an initial height equal to 3:

H(t) = 3*2^{t/30}

4 0
2 years ago
Is the expression 9(−4x−3) equivalent to the expression −36x−27.?
LekaFEV [45]

Answer:

No they are not equivilant. −36x−27 = 972 & 9(−4x−3) = 108.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find the following integral
ololo11 [35]

There's nothing preventing us from computing one integral at a time:

\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2

\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2

\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx

Expand the integrand completely:

x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x

Then

\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}

4 0
2 years ago
Other questions:
  • Can you guy tell the answer write please
    14·2 answers
  • What’s the answer to this
    14·1 answer
  • -9+100 divided by 4•3
    13·1 answer
  • On a school trip, the ratio of the teachers to students is 2:21. The ratio boys to girls is 4:3. If there are 18 girls girls on
    14·1 answer
  • please, someone, help me with math I really need help if ur willing to help me with full calculations please please reply!!
    5·1 answer
  • Help me............ explain​
    5·1 answer
  • Irene eats 45 grams of fiber every day. Each gram equals 100% of fiber. How many grams did she have (in %)?
    9·2 answers
  • PLS HELP WILL MARK BRAINLIEST
    12·2 answers
  • Find+the+z-scores+that+separate+the+middle+69%+of+the+distribution+from+the+area+in+the+tails+of+the+standard+normal+distributio
    7·1 answer
  • The temperature at 5 P.M. is 20°F. The temperature at 10 P.M. is -5°
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!