1st box: 2a (subtract 2a from both sides)
2nd box: 3 (add 3 to both sides)
3rd box: 10 (add 7+3)
4th and 5th box: 2 (divide both by 2)
6th box: 5 (10/2=5)
Answers
A. <
Explanation
-2.875_____ <u>-</u><u>9</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>8
-2.875_____-1.125
so
-2.875 < -1.1225
cause -2 is greater than -1
I answer this question atleast once a day hahah.
Firstly convert 1/2 into quarters.
1/2 = 2/4 (double the numerator and denominator)
Then add the two, 2/4 + 1/4 (add the numerators)
2/4 + 1/4 = 3/4
The answer is: 3/4
Answer:
for brand A it required 41 bags and for brand B is required 56 bags
Step-by-step explanation:
The computation is shown below:
Let us assume Brand A be x
And, brand B be y
Now according to the question
The following equations are
8x + 7y = 720
4x + 6y = 500
Multiply by 2 in equation 2
8x + 7y = 720........(1)
8x + 12y = 1000..........(2)
Now subtract equation 1 from equation 2
5y = 280
y = 56 bags
And, x is
8x + 7(56) = 720
8x + 392 = 720
8x = 328
x = 41 bags
hence, for brand A it required 41 bags and for brand B is required 56 bags
Answer:
See below
Step-by-step explanation:
Let side AB equal x. Since triangle ABC is equilateral, sides AB, BC, and Ac are all the same length, x. In any isosceles triangle(equilateral is a type of isosceles triangle) the median is the same as the altitude and angle bisector. This means we can say that AD is also a median. A median splits a side into two equal sections, so we can say BD = DC = x / 2. We are given that DC = CE, so we can also say CE = DC = x / 2. Now, we can use the pythagorean theorem to find the length of AD. So we get the equation:
AB^2 - BD^2 = AD^2
We have the values of AB and BD, so we can substitute them and solve for AD:
x^2 - (x/2)^2 = AD^2
x^2 - x^2 / 4 = AD^2
AD^2 = 3x^2 / 4
AD = x√3 / 2
DE is equal to the sum of DC and CE because of segment addition postulate, so we can say DE = DC + CE = x / 2 + x/ 2 = x. We can again use the pythagorean theorem to find the length of AE:
AD^2 + DE^2 = AE^2
(x√3 / 2)^2 + x^2 = AE^2
3x^2 / 4 + x^2 = AE^2
AE^2 = 7x^2 / 4
AE = x√7 / 2
Now, we know(from before) that AE squared is 7x^2 / 4. We can say EC squared is x^2 / 4 because EC is x / 2 and x / 2 squared is x^2 / 4. We can also notice that AE squared is 7 times EC squared because 7x^2 / 4 = 7 * x^2 / 4
Therefore, we can come to the conclusion AE^2 = 7 EC^2