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Mars2501 [29]
2 years ago
9

Simplify: 5 + p > 3 A.p < 8 B.p > 8 C.p < - 2 D.p > - 2

Mathematics
2 answers:
lianna [129]2 years ago
6 0

Answer:

D) p > -2

Step-by-step explanation:

5 + p > 3

5 + p - 5 > 3 - 5

p > -2

Viktor [21]2 years ago
6 0
Answer D.p>- 2
Step by step
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Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the following
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The perpendicular equation would include a slope that is the opposite reciprocal of the original slope.

Steps:
1. Get x to the other side in the original equation. This making the slope -4 or -4/1.

2. Turn the slope into it’s opposite reciprocal m = 1/4.

3. If you use point-slope form, y - y1 = m( x - x1 ), you can substitute y1 and x1 with the numbers in the point given. But since we previously found the opposite reciprocal, we will replace “m” as well. *By the way, the subtraction of a negative makes a positive. [y + 3 = 1/4( x + 4 )]

4. Solve:
A: Distribute (y + 3 = 1/4x + 1)
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Perpendicular Equation: y = 1/4x - 2
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a beauty salon buys bottles of styling gel for $4.50 per bottle and marks up the price by 40%. for what price does the salon sel
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40%=0.4
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Anna is buying a car and needs to borrow $23,500 from a bank offering a monthly interest rate of 0.4%. If Anna makes monthly pay
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3 years ago
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Gwar [14]
I'm not sure, but what I got was -8.5, since it is only stating that it is -17 and 5, and you need to figure out Point B, when it is between A and 0. So, you don't pay attention to 1-5. You only want -17 through 0. -17 divided by two would be -8.5
5 0
3 years ago
Show the work please
Kay [80]

Answer:

1) (x + 3)(3x + 2)

2) x= +/-root6 - 1 by 5

Step-by-step explanation:

3x^2 + 11x + 6 = 0 (mid-term break)

using mid-term break

3x^2 + 9x + 2x + 6 = 0

factor out 3x from first pair and +2 from the second pair

3x(x + 3) + 2(x + 3)

factor out x+3

(x + 3)(3x + 2)

5x^2 + 2x = 1 (completing squares)

rearrange the equation

5x^2 + 2x - 1 = 0

divide both sides by 5 to cancel out the 5 of first term

5x^2/5 + 2x/5 - 1/5 = 0/5

x^2 + 2x/5 - 1/5 = 0

rearranging the equation to gain a+b=c form

x^2 + 2x/5 = 1/5

adding (1/5)^2 on both sides

x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2

(x + 1/5)^2 = 1/5 + 1/25

(x + 1/5)^2 = 5 + 1 by 25

(x + 1/5)^2 = 6/25

taking square root on both sides

root(x + 1/5)^2 = +/- root(6/25)

x + 1/5 = +/- root6 /5

shifting 1/5 on the other side

x = +/- root6 /5 - 1/5

x = +/- root6 - 1 by 5

x = + root6 - 1 by 5 or x= - root6 - 1 by 5

4 0
3 years ago
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