The perpendicular equation would include a slope that is the opposite reciprocal of the original slope.
Steps:
1. Get x to the other side in the original equation. This making the slope -4 or -4/1.
2. Turn the slope into it’s opposite reciprocal m = 1/4.
3. If you use point-slope form, y - y1 = m( x - x1 ), you can substitute y1 and x1 with the numbers in the point given. But since we previously found the opposite reciprocal, we will replace “m” as well. *By the way, the subtraction of a negative makes a positive. [y + 3 = 1/4( x + 4 )]
4. Solve:
A: Distribute (y + 3 = 1/4x + 1)
B: Subtract 3 from both sides (y = 1/4x -2)
Perpendicular Equation: y = 1/4x - 2
40%=0.4
0.4+1=1.4
4.5(1.4)=6.3
The answer is $6.30
I'm not sure, but what I got was -8.5, since it is only stating that it is -17 and 5, and you need to figure out Point B, when it is between A and 0. So, you don't pay attention to 1-5. You only want -17 through 0. -17 divided by two would be -8.5
Answer:
1) (x + 3)(3x + 2)
2) x= +/-root6 - 1 by 5
Step-by-step explanation:
3x^2 + 11x + 6 = 0 (mid-term break)
using mid-term break
3x^2 + 9x + 2x + 6 = 0
factor out 3x from first pair and +2 from the second pair
3x(x + 3) + 2(x + 3)
factor out x+3
(x + 3)(3x + 2)
5x^2 + 2x = 1 (completing squares)
rearrange the equation
5x^2 + 2x - 1 = 0
divide both sides by 5 to cancel out the 5 of first term
5x^2/5 + 2x/5 - 1/5 = 0/5
x^2 + 2x/5 - 1/5 = 0
rearranging the equation to gain a+b=c form
x^2 + 2x/5 = 1/5
adding (1/5)^2 on both sides
x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2
(x + 1/5)^2 = 1/5 + 1/25
(x + 1/5)^2 = 5 + 1 by 25
(x + 1/5)^2 = 6/25
taking square root on both sides
root(x + 1/5)^2 = +/- root(6/25)
x + 1/5 = +/- root6 /5
shifting 1/5 on the other side
x = +/- root6 /5 - 1/5
x = +/- root6 - 1 by 5
x = + root6 - 1 by 5 or x= - root6 - 1 by 5