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Mars2501 [29]
2 years ago
9

Simplify: 5 + p > 3 A.p < 8 B.p > 8 C.p < - 2 D.p > - 2

Mathematics
2 answers:
lianna [129]2 years ago
6 0

Answer:

D) p > -2

Step-by-step explanation:

5 + p > 3

5 + p - 5 > 3 - 5

p > -2

Viktor [21]2 years ago
6 0
Answer D.p>- 2
Step by step
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Which of the following points lies on the line?
Bond [772]

Answer:

C. (3,-3)

Step-by-step explanation:

5x + 3y = 6

5(3) + 3(-3) = 6

15 + (-9) = 6

therefore point lies on the line

8 0
2 years ago
A cable 20 feet long connects the top of a flagpole to a point on the ground that is 16 feet from the base of the pole. How tall
timurjin [86]
Think of it like a triangle.

The flagpole is vertical and is at 90° to the ground. This makes a right-angle to the ground, which is flat.

Since we have two sides of the triangle already, and they are in a ratio of ?? : 16 : 20 = ?? : 4 : 5, that means that because the triangle is a right-angled triangle, the third and last side must be 3 to complete the ratio! (This is called 'Pythagoras')

Since the other sides were divided by 4 to get the simple ratio, we must multiply 3 to get the actual ratio! 3 × 4 = 12 ft tall flagpole.

3 0
3 years ago
Which percent is equivalent to 3/5 ?
sergeinik [125]
%60 is equivalent to 3/5
5 0
3 years ago
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sammy [17]

Answer:

C maybe.........

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Custom Office makes a line of executive desks. It is estimated that the total cost for making x units of their Senior Executive
Ivan

Answer:

(a) The average cost function is \bar{C}(x)=95+\frac{230000}{x}

(b) The marginal average cost function is \bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

Step-by-step explanation:

(a) Suppose C(x) is a total cost function. Then the average cost function, denoted by \bar{C}(x), is

\frac{C(x)}{x}

We know that the total cost for making x units of their Senior Executive model is given by the function

C(x) = 95x + 230000

The average cost function is

\bar{C}(x)=\frac{C(x)}{x}=\frac{95x + 230000}{x} \\\bar{C}(x)=95+\frac{230000}{x}

(b) The derivative \bar{C}'(x) of the average cost function, called the marginal average cost function, measures the rate of change of the average cost function with respect to the number of units produced.

The marginal average cost function is

\bar{C}'(x)=\frac{d}{dx}\left(95+\frac{230000}{x}\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g\\\\\frac{d}{dx}\left(95\right)+\frac{d}{dx}\left(\frac{230000}{x}\right)\\\\\bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})\\\\\lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)\\\\=\lim _{x\to \infty \:}\left(95\right)+\lim _{x\to \infty \:}\left(\frac{230000}{x}\right)\\\\\lim _{x\to a}c=c\\\lim _{x\to \infty \:}\left(95\right)=95\\\\\mathrm{Apply\:Infinity\:Property:}\:\lim _{x\to \infty }\left(\frac{c}{x^a}\right)=0\\\lim_{x \to \infty} (\frac{230000}{x} )=0

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})= 95

6 0
3 years ago
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