All categories

3 years ago

Help me with this please everyone

Mathematics

1 answer:

cupoosta [38]3 years ago

3 0

First, let's simplify each expression by combining like terms:

A: 9x-3x-4 = 6x-4

B: 12x-4 = 12x-4 (Already Combined terms)

C: 5x+x-4 = 6x-4

When looking at the list of equations, it is clear that only Expression A and C are equivalent. Brianna failed to combine like terms and plug in more points than 0.

I Hope this Helps!
-Sinnamin

You might be interested in

Which of the aaa-values satisfy the following inequality?

mina [271]

Answer:

a = 3

Step-by-step explanation:

When you add the given value for a with 7, the resulting answer must be less than 11.

In this case, if: a = 3

Plug in 3 for a in the equation:

7 + a < 11

7 + 3 < 11

10 < 11 (True).

A) a = 3 is your answer.

7 0

2 years ago

Hi guys, can anyone help me with this triple integral? Many thanks:)

Crank

Another triple integral. We're integrating over the interior of the sphere

$x^2+y^2+z^2=2^2$

Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

$y^2=4-x^2-z^2$

x is the inner integral so at this point we conservatively say its zero. That means y goes from $-\sqrt{4-z^2}$ and $+\sqrt{4-z^2}$

Similarly the inner integral x goes between $\pm-\sqrt{4-y^2-z^2}$

So we rewrite the integral

$\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz$

Let's work on the inner one,

$\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz$

There's no z in the integrand, so we treat it as a constant.

$=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}$

So the middle integral is

$\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy$

I gotta go so I'll stop here, sorry.

7 0

2 years ago

Read 2 more answers

Solve for x 7|x + 3| + 5 = 40

Harman [31]

Answer:

4.6 or 4.57

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

How to find the value of each power

Inessa [10]

Exponent of a number says how many times.

2³

The 2 is the base number, while the little 3 is the exponent.

2³ = 2 x 2 x 2 = 8

Basically, you would just have to do two, three times.

Very time when you get the hang of it !!

4 0

3 years ago

The ratio of good markers to not working markers in a classroom is 5:2. There are 14 markers. How many good markers are there?

Alchen [17]

Answer:

At least 5.

Step-by-step explanation:

5:2 = 2.5 markers out of five are not faulty.

14 markers divided by 2.5 = 5.6.

I hope this helps

3 0

3 years ago

Read 2 more answers