Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
A example can be Keith has $500 in a savings account at the beginning of the summer. He wants to have at least $200 in the account by the end of the summer. He withdraws $25 each week for food, clothes, and movie tickets. The answer would be Any more than 12 weeks and his account balance would be less than $200. Any number of weeks less than 12 and his account would stay above $200.
Solutions
⇒15 Cookie to 40 brownies can be written as 15:40
⇒15:40 is the ratio we have to simplify
The GCF of 15 and 40 is 5 so we divide them by 5
15 ÷ 5 = 3
40 ÷ 5 = 8
3:8 is in simplest form
#1 is -32
#2 is -11
#3 is -5
#4 is 6
Answer:
Step-by-step explanation:
Salvage value=$1000
Purchased value=$11,000
In order to find the balance in accumulated depreciation at december 31,2015 using the units of activity we will use the following formula:
In the above equation $10000 came from Purchased value - salvage Value
