3 years ago

How do i write an equation for a graph

Mathematics

1 answer:

laiz [17]3 years ago

4 0

Like for slope would be y=mx+b

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lilavasa [31]

Answer:

Mass of the liquid in the tank will be $1.45\times 10^8kg$

Step-by-step explanation:

We have given volume of tar $V=3.20\times 10^5gallon$

1 gallon = 3.785 liter

So $3.20\times 10^5gallon=3.20\times 10^{5}\times 3.785=12.112\times 10^5liter$

Specific gravity = 1.2

Density of water $=1000kg/m^3$

We know that specific gravity $=\frac{density\ of\ liquid}{density\ of\ water}$

$1.2=\frac{density\ of\ liquid}{density\ of\ water}$

Density of liquid $=1200kg/m^3$

So mass of liquid = volume × density

= $12.112\times 10^5\times 1200=1.45\times 10^8kg$

So mass of the liquid in the tank will be $1.45\times 10^8kg$

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$\large \mathfrak{Solution : }$

Yes, it's true because the value of LHS = RHS if we solve it .

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