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Anni [7]
2 years ago
11

There are a total of 722 students at dustins school

Mathematics
2 answers:
mylen [45]2 years ago
4 0

Answer:

I had NOOOOO clue but can I get braonlost

Lina20 [59]2 years ago
3 0

Answer:

whats the question skrrrrrrrrt

Step-by-step explanation:

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Ricky walked a total of 4 3/4
Helga [31]

Answer:

19

Step-by-step explanation:

Is he stop every 1/4 mile you get 19

There are 4 1/4 miles in every mile. 4x4(Equation of total 1/4th's in 4 miles) is 16. Add 3 more 1/4th's to get 19

Hope this helps!

7 0
3 years ago
What's P squared -1 factorised?
Aleksandr [31]
(p+1) (p-1). solved this on paper . hope it helps .
8 0
3 years ago
The volume
Sedaia [141]
\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
&&  y={{ k }}x
\end{array}\\ \quad \\


and also

\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
&&y=\cfrac{{{  k}}}{x}
\end{array}


now, we know that V varies directly to T and inversely to P simultaneously
thus\bf V=T\cdot \cfrac{k}{P}

so     \bf V=T\cdot \cfrac{k}{P}\qquad 
\begin{cases}
V=42\\
T=84\\
P=8
\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k
\\\\\\
V=\cfrac{4T}{P}\qquad now\quad 
\begin{cases}
V=74\\
P=10
\end{cases}\implies 74=\cfrac{4T}{10}\implies 185=T
7 0
3 years ago
A cone has a diameter of 4 centimeters and a height that is 6 times the diameter. Using 3.14 for pi, which of the following can
Irina-Kira [14]
I hope this helps you

4 0
3 years ago
which property is shown? 20×5×6=20×6×5 A commutative property B distibutivr C associative property or D none of these are correc
Contact [7]

A: communicative property, it is this because communicative property allows you to switch around the order.

5 0
3 years ago
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