Compensation for the year:$51,810(deducting vehicle expense)
An employee makes 48,700+1,530(health insurance)+2,810(paid time)=
53,040. Also they receive 0.53 per mile x 9,000 miles=4,770
53,040 +4,770=57,810(employment compensation)
Personal work vehicle expense: 500 x 12 months=6,000
57,810 - 6,000= 51,810
Answer:
(8, 15 and 17)
Step-by-step explanation:




Answer:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Of the 2809 people who responded to survey, 1634 stated that they currently use social media.
This means that 
98% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
It would be 82 2/3 since 1/3 minis 2/3 would equal -1/3 you subtract that from 83 and get 82 2/3