All categories

3 years ago

Idk how to solve these questions

Mathematics

2 answers:

Anuta_ua [19.1K]3 years ago

5 0

Of means multiply

3/5 *n=30

3/5 5/3 cancels than you do 30 *5/3 =50

The answer is 50 you can check your answer by doing 3/5 *50=150/5 or 30 so it's correct .

BartSMP [9]3 years ago

4 0

#is5 how I got the answer well it say 10times a number so u know u gotta multiply 10by a number ,then it said increase by 9 there it then said the number was 59 so I said 10times 5 +9=59 in other words 10x +9=59
first your gonna bring over the 9 to the other side of the equation so ur gonna have 10x=59-9cause if it was positive first then the sign changed to negative when u brought it over to the other side so now u subtract 9from 59and u get 50so now u got 10x =50 so now ur gonna divide both sides by 10to get the x by itself so now on one side u got 10÷19x and the other side 50÷10 now u have x=5

You might be interested in

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

a chef uses 5 2/5 pounds of ground beef to make a hamburger and 2 1/4 pounds of ground beef to make meatloaf. the ground beef co

Lisa [10]

Answer:

16 packages

Step-by-step explanation:

5 2/5 + 2 1/4 Use the common denominator of 20

5 8/20 + 2 5/20

7 13/20

I know that I will need 14 packages for the 7 pounds. For the fraction part, 10/20 would be half, so I would need to buy a half pound for that, but I need 13/20 which would be more than a half pound, so I will need to buy 2 more pounds for the fraction part.

14 + 2 = 16

8 0

1 year ago

2.5g + 3.14g + 6g + 12.32g

klio [65]

Answer:

23.96g

Step-by-step explanation:

Make sure to thank me!!!

7 0

3 years ago

N − 7.32 / 2 = 1.04<br><br> What is "n"?

Pachacha [2.7K]

Answer:

n= 4.7

Step-by-step explanation:

n+−3.66=1.04

n−3.66=1.04

Step 2: Add 3.66 to both sides.

n−3.66+3.66=1.04+3.66

n=4.7

Answer:

n=4.7

7 0

3 years ago

Samuel can type nearly 40 words per minute. Use this information to find the number of hours it would take him to type 3.8 × 105

lora16 [44]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers