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swat32
3 years ago
9

Janelle and three of her friends bought four smoothies for a total of $3. If she purchases smoothies on another day for herself

and 9 of her friends, how much money will she spend?
Mathematics
2 answers:
Lena [83]3 years ago
7 0
She will spend $7.50 in total.
bogdanovich [222]3 years ago
4 0
Janelle will spend $7.50 because each smoothie costs .75 cents.
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There are 3 3/4 cups of flour 1 1/2 cups of sugar 2/3 cups of brown sugar and 1/4 cups of oil in a cake mix how many cups of in
maxonik [38]

Answer:

7 6/12

Step-by-step explanation:

8 0
3 years ago
Xavier rides his bike 5 1/4 miles or 82% of his goal for the day. What is his goal for the day?
Leno4ka [110]
Use ratio and proportion

5.25/x= 82/100
cross multiply
82 x= 525
     x= 6.4 miles

Hope this helps
8 0
3 years ago
Can somebody help me please ​
aleksklad [387]

Answer:

I think it's -2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
If anyone could help out with this one i would really appreciate it <br><br> f(2)=?
algol13

Answer:

f(2) = 0

Step-by-step explanation:

Function f(t) is defined in three different ways depending on the value of t.

For t = 8, function f(t) is -64/t.

For t = 10, function f(t) is 14 - t.

We are not asked about f(8) or f(10). We are asked about f(2). The third definition of function f(t) is for all values of t that are not 8 or 10. 2 is not 8 or 10, so use the third definition of function f(t) and plug in 2 for t.

f(t) = t^2 - 3t + 2 for t not equal to 8 or 10.

f(2) = 2^2 - 3(2) + 2

f(2) = 4 - 6 + 2

f(2) = 0

6 0
3 years ago
Help appreciated on question in image!<br> Thanks:)
Verdich [7]

Answer:

x=-1,\:x=-7,\:x=i,\:x=-i

Step-by-step explanation:

Considering the equation

x^4+8x^3+8x^2+8x+7=0

Solving

x^4+8x^3+8x^2+8x+7

\mathrm{Factor\:}x^4+8x^3+8x^2+8x+7:\quad \left(x+1\right)\left(x+7\right)\left(x^2+1\right)

As

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=7,\:\quad a_n=1

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:7,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:7}{1}

-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1

=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]

Solving

\frac{x^4+8x^3+8x^2+8x+7}{x+1}

=x^3+7x^2+x+7

Putting \frac{x^4+8x^3+8x^2+8x+7}{x+1} =  x^3+7x^2+x+7 in equation [A]

So,

\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]

=\left(x+1\right)x^3+7x^2+x+7

As

x^3+7x^2+x+7=\left(x+7\right)\left(x^2+1\right)

So,

Equation [A] becomes

=\left(x+1\right)\left(x+7\right)\left(x^2+1\right)

So,  the polynomial equation becomes

\left(x+1\right)\left(x+7\right)\left(x^2+1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)\mathrm{Solve\:}\:x+1=0:\quad x=-1

\mathrm{Solve\:}\:x+7=0:\quad x=-7

\mathrm{Solve\:}\:x^2+1=0:\quad x=i,\:x=-i

\mathrm{The\:solutions\:are}

x=-1,\:x=-7,\:x=i,\:x=-i

Keywords: polynomial equation

Learn polynomial equation from brainly.com/question/12240569

#learnwithBrainly

5 0
3 years ago
Read 2 more answers
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