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3 years ago

If marching bands vary from 21 to 49 player, which numbers of players can be arranged in the greatest number of rectangles?

1 answer:

5 0

Hmm. a rectangle?ok then, least number of rectangles needed-6.
. . .
. . . ( rectangle)
so, 6 x 8=48(greatest multiple of 6 from between 21 and 49)
48 players are most, so 8 rectangles

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Robert accepted a new job at a company with a contract guaranteeing annual raises. Let S represent Robert's salary after working

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Answer:

74,000

Step-by-step explanation:

In the year where he got 104,000 the year before he got 6,000 less. The year before 98,000 he got 12,000 less which means that now it would just be 86,000-12,000=74,000

I think this is right but you can double check on a calculator

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3 years ago

Mr. Brown's class is collecting books for a book drive. They started with 2 books. On the first day, they had 6 books. On the se

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3 years ago

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4.572 kilometers is the answer.

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3 years ago

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Differentiate \[\ln \sin^2 x\]

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Y = ln {[sin(x)]^2}

use the chain rule

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3 years ago

A city planner designs a park that is a quadrilateral with vertices at J(-3,1), K(1,3), L(5,-1), and M(-1,-3). There is an entra

Ksivusya [100]

The Quadrilateral is JKLM,

let $M_{JK}, M_{KL}, M_{LM}, M_{JM},$ be the midpoints of JK, KL, LM and JM respectively.

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Given any 2 point P(m,n) and Q(k,l),

the coordinates of the midpoint of the line segment PQ are given by the formula:

$M_{PQ}=( \frac{m+k}{2} ,
\frac{n+l}{2})$ ,

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thus the coordinates of points $M_{JK}, M_{KL}, M_{LM}, M_{JM},$

are as follows:

$M_{JK}= (\frac{-3+1}{2}, \frac{1+3}{2})=(-1,2), \\\\M_{KL}= (\frac{1+5}{2}, \frac{3-1}{2}=(3,1), \\\\M_{LM}= (\frac{5-1}{2}, \frac{-1-3}{2})=(2, -2),\\\\ M_{JM}= (\frac{-3-1}{2}, \frac{1-3}{2})=(-2,-1)$

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The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:

$|PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}
}$

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thus the distances connecting the opposite entrances can be calculated as follows:

$|M_{JK},M_{LM}|= \sqrt{ (-1-2)^{2} + (2-(-2))^{2} }= \sqrt{9+16}=5$

$|M_{KL}M_{JM}|= \sqrt{ (3-(-2))^{2} + (1-(-1))^{2}}= \sqrt{25+4}= \sqrt{29}=5.39$

Thus the total distance of the paths joining the opposite entrances is

5+5.39 units = 50 m + 53.9 m = 104 m (rounded to the nearest meter)

Answer: 104 m

8 0

3 years ago