The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Answer:
4.
Step-by-step explanation:
2 to the second power = 2^2.
2^2 means 2*2 = 4.
The 2 in ^2 is called the 'exponent' .
Note 3^3 = 3*3*3
and 5^5 = 5*5*5*5*5.
The total cost is the dependant variable and the number of tickets along with flat out price is the independent variable.
The equation would be y = 1.25x + ?
You would insert 25 for x which equals 31.25 and insert 43.75 for y.
43.75 = 31.25 + ? Then subtract 31.25 from both sides of the equation and you would get....
12.5 = ?
That is your flat rate to get in to the fair
A would be the correct answer because the y variable only has a coefficient of 1. So we would solve for y, which would get us y=3x+5, then we would substitute the value in the second equation which would look like -4x+5(3x+5)=58. Hope this helpss. :)
